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2 years ago

Which is the best definition of an Isosceles Triangle ?

Mathematics

1 answer:

baherus [9]2 years ago

6 0

Answer:

A) but it is not a good choice.

Step-by-step explanation:

I don't like A much. An Isosceles triangle has 2 congruent sides. If all three are congruent, it is equilateral.

Of the three choices however, it is A. B is a scalene triangle and C is as stated, equilateral.

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X f(x)

Montano1993 [528]

I would say A hope I helped

8 0

3 years ago

Solve using the Quadratic Formula. 3x2 + 2x + 1 = 0

Crazy boy [7]

Answer:

Hi! The correct answer is x= -7/2

Step-by-step explanation:

Solve the rational equation by combining expressions and isolating the variable x.

8 0

3 years ago

A sphere is inscribed in a cube with a volume of 64 cubic inches. What is the volume of the sphere? Round your answer to the nea

erma4kov [3.2K]

Answer:

the volume of the sphere is

$33.51 in^{3}$

Step-by-step explanation:

This problem bothers on the mensuration of solid shapes, sphere and cube.

Given data

Volume of cube v = 64 cubic inches

since we are dealing with a cube the height and the radius of the sphere is same as the sides of the cube,

we know that volume of cube is expressed as

$v= l*b*h$

$v=l^{3}$

$64= l^{3}$

$l= \sqrt[3]{64}$

$l= 4 in$

also diameter d=length l

Diameter d= $4in$

Radius r = $\frac{d}{2}$ = $\frac{4}{2}$ = ${2 in}$

Height h= $4in$

we know that the volume of a sphere is given by

$v= \frac{4}{3} \pi r^{3}$

substituting into the formula we have

$v= \frac{4}{3} \ *3.142*2^{3} \\v=\frac{4*3.142*8}3} \\v= \frac{100.54}{3} \\v= 33.52in^{3}$

8 0

3 years ago

Please help

ASHA 777 [7]

Answer:

(-6,4)

Step-by-step explanation:

The equations are:

$x^2+4y^2=100\\4y-x^2=-20$

Solving for x^2 of the 2nd equation and putting that in place of x^2 in the 2nd equation we have:

$4y-x^2=-20\\x^2=4y+20\\-------\\x^2+4y^2=100\\4y+20+4y^2=100$

Now we can solve for y:

$4y+20+4y^2=100\\4y^2+4y-80=0\\y^2+y-20=0\\(y+5)(y-4)=0\\y=4,-5$

So plugging in y = 4 into an equation and solving for x, we have:

$x^2=4y+20\\x=+-\sqrt{4y+20} \\x=+-\sqrt{4(4)+20} \\x=+-\sqrt{36} \\x=6,-6$

So y = 4 corresponds to x = 6 & x = -6

The pairs would be

(6,4) & (-6,4)

we see that (-6,4) falls in the 2nd quadrant, thus this is the solution we are looking for.

5 0

3 years ago

A dogs weighs 7 pounds and triples each year for two years. How much does the dog weigh?

Tanya [424]

Year 1: 7lbs x 3years= 21lbs
Year 2: 21lbs x 3years = 63lbs

5 0

3 years ago

Read 2 more answers