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san4es73 [151]
3 years ago
13

Use the functions a(x) = 3x + 10 and b(x) = 2x − 8 to complete the function operations listed below.

Mathematics
1 answer:
Gnoma [55]3 years ago
7 0
For part A, you simply add the two functions a(x) and b(x). The resulting function is then (a+b)(x) = 5x +2.

For part B, you multiply the functions a(x) and b(x). Using the FOIL method, we obtain, 6x^2 -24x + 20x - 80. Simplifying, we get, (a*b)(x) =  6x^2 -4x - 80.

For part C, you replace x in the function a(x) with the expression from b(x). This results to: a[b(x)] = 3(2x - 8) +10. Simplifying, a[b(x)] = 6x - 14.
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Explanation

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(3 + xz)(–3 + xz) = (3 + xz)(xz -3)

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(y² – xy)(y² + xy) = y⁴+xy³-xy³-x²y²

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(64y2 + x2)(–x2 + 64y2)= (64y²+x²)(64y²-x²)

                                      = 4096y⁴-64y²x²+64y²x²-x⁴

                                      = 4096y⁴ - x⁴

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Step-by-step explanation:

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6 0
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