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natta225 [31]
2 years ago
5

Pleaseeeeeeeeeee help me ​

Mathematics
1 answer:
choli [55]2 years ago
8 0

Answer:

144

Step-by-step explanation:

4 x 4 = 16 x 2 = 32

7 x 4 = 28 x 2 = 56

7 x 4 = 28 x 2 = 56

add them up

144

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5<br> 0 = - in<br> =<br> in quadrant II<br> Given cos =<br> Find sin<br> 3
____ [38]

Answer:

sinΘ = \frac{2}{3}

Step-by-step explanation:

using the identity

sin²x + cos²x = 1  ( subtract cos²x from both sides )

sin²x = 1 - cos²x ( take square root of both sides )

sinx = ± \sqrt{1-cos^2x}

given

cosΘ = - \frac{\sqrt{5} }{3} , then

sinΘ = ± \sqrt{1-(-\frac{\sqrt{5} }{3})^2 }

        = ± \sqrt{1-\frac{5}{9} }

        = ± \sqrt{\frac{4}{9} }

        = ± \frac{2}{3}

since Θ is in quadrant II where sinΘ > 0 , then

sinΘ = \frac{2}{3}

7 0
2 years ago
Knock his dreads off​
skad [1K]

Answer:

oof

Step-by-step explanation:

4 0
2 years ago
Read 2 more answers
Which of the following shows the correct evaluation for the exponential expression 6 over 7 to the power of 2?
yaroslaw [1]
For this case we have the following expression:
 6 over 7 to the power of 2
 (6/7) ^ 2
 By power properties we can rewrite the expression as:
 (6/7) * (6/7)
 Calculating we have:
 (6/7) * (6/7) = 36/49
 Answer:
 
6 over 7 times 6 over 7 equals 36 over 49
5 0
3 years ago
Please Help!
AURORKA [14]
Obtuse, it does not fit Pythagoreans for a right triangle, two sides are not equal to be isosceles
6 0
3 years ago
The house was bought for $125,000 in 1990, the overage rate is 7.85%, what year will the purchase of the house be worth 3 times
olga55 [171]

Answer: 2005

Step-by-step explanation:

Exponential function to determine the value of item after t years,

f(x)=A(1+r)^t , where r= rate of growth, A=Initial value.

As per given , A = 7.85% = 0.0785

A = $125,000

Substitute all values in function, we get

f(x)=125000(1+0.785)^t

When f(x)= 3A , then

3A=A(1.0785)^t\\\\\Rightarrow\ 3=(1.0785)^t

Taking tog on both sides , we get

\ln 3=t\ln 1.0785\\\\\Rightarrow\ t=\dfrac{\ln 3}{\ln 1.0785}\\\\\Rightarrow t=\dfrac{1.09861228867}{0.0755711868471}\approx15

The year will be 1990+15= 2005

Hence, the required year = 2005

8 0
3 years ago
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