2.
1 answer:
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This type of problems are solved by partitioning the figure into rectangles, whose areas we can find easily.
Picture 1)
From the point denoted by E, draw two altitudes towards the sides AG and AC.
Since ED is 3, then BC is 3. Thus, AB=4-3=1.
Since EF is 1, then HG is 1, so AH=3-1=2.
The area of the figure is equal to the area of rectangle ACDH + the area of the square HEFG.
That is, the area of the figure is 4*2+1*1=8+1=9 (square in).
Picture 2)
As in the first part, draw the altitudes EB and EH from point E.
GF is 5, so AB is 5. This means that BC=7-5=2 (in).
FE is 3, so GH is 3, that is HA=6-3=3.
Thus, Area(figure)=Area(ABFG)+Area(BCDE)=5*6+2*3=30+6=36 (square in.)
Answer: 9 (square in); 36 (square in.)
Picture 1)
From the point denoted by E, draw two altitudes towards the sides AG and AC.
Since ED is 3, then BC is 3. Thus, AB=4-3=1.
Since EF is 1, then HG is 1, so AH=3-1=2.
The area of the figure is equal to the area of rectangle ACDH + the area of the square HEFG.
That is, the area of the figure is 4*2+1*1=8+1=9 (square in).
Picture 2)
As in the first part, draw the altitudes EB and EH from point E.
GF is 5, so AB is 5. This means that BC=7-5=2 (in).
FE is 3, so GH is 3, that is HA=6-3=3.
Thus, Area(figure)=Area(ABFG)+Area(BCDE)=5*6+2*3=30+6=36 (square in.)
Answer: 9 (square in); 36 (square in.)
First add 3 to both sides (what you do on one side you must do to the other). Since 3 is being subtracted, addition (the opposite of subtraction) will cancel it out (make it zero) from the right side and bring it over to the left side.
2 < u - 3
2 + 3 < u - 3 + 3
5 < u - 0
5 < u
For the graph will you have a empty or colored in circle?
If the symbol is ≥ or ≤ then the circle will be colored in. This represents that the number the circle is on is included.
If the symbol is > or < then the circle will be empty. This represents that the number the circle is on is NOT included.
Which direction will the ray go?
If the variable is LESS then the number then the arrow will go to the left of the circle.
If the variable is MORE then the number then the arrow will go to the right of the circle.
In this case your inequality is:
5 < u OR u > 5
aka 5 is less then u OR u is greater then 5
This means that the graph will have an empty circle and the arrow will go to the right of 5. Look at image below.
Hope this helped!
~Just a girl in love with Shawn Mendes
