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2 years ago

What is the value of f(1)?

Mathematics

2 answers:

vekshin12 years ago

8 0

Answer:

The option (A) is correct that is f(1) =0 .

Step-by-step explanation:

We can see from the given graph that it is step function

and also interpret as :

value of function at value of x are:

at x= 1 is f(1) =0

at x=2 is f(1) =1

at x=4 is f(1) =2

at x= -2 is f(1) = -1

at x= -4 is f(1) = -2

Hence, the option (A) is correct that is f(1) =0 .

Anni [7]2 years ago

6 0

Check the picture below.

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Step-by-step explanation:

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solniwko [45]

For this case we have to:

Let $u = x + 1$

So:

$u ^ 2-4u + 2 = 0$

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Substituting:

$u = \frac {- (- 4) \pm \sqrt {(- 4) ^ 2-4 (1) (2)}} {2 (1)}\\u = \frac {4 \pm \sqrt {16-8}} {2}\\u = \frac {4 \pm \sqrt {8}} {2}\\u = \frac {4 \pm \sqrt {2 ^ 2 * 2}} {2}\\u = \frac {4 \pm2 \sqrt {2}} {2}$

The solutions are:

$u_ {1} = \frac {4 + 2 \sqrt {2}} {2} = 2 + \sqrt {2}\\u_ {2} = \frac {4-2 \sqrt {2}} {2} = 2- \sqrt {2}$

Returning the change:

$2+ \sqrt {2} = x_ {1} +1\\x_ {1} = 1 + \sqrt {2}\\2- \sqrt {2} = x_ {2} +1\\x_ {2} = 1- \sqrt {2}$

Answer:

$x_ {1} = 1 + \sqrt {2}\\x_ {2} = 1- \sqrt {2}$

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2 years ago

Read 2 more answers