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katovenus [111]
3 years ago
10

In each function below, determine:

Mathematics
1 answer:
saveliy_v [14]3 years ago
4 0

<em>Answer </em><em>:</em><em> </em>

For a function to be one to one it must

For a function to be one to one it mustpass the horizontal line test. For every

For a function to be one to one it mustpass the horizontal line test. For everyoutput value f(x) there is only one

For a function to be one to one it mustpass the horizontal line test. For everyoutput value f(x) there is only oneinput value x..

<em>Please </em><em>mark </em><em>me </em><em>as</em><em> </em><em>brainliest</em><em> </em><em>❤️</em>

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liraira [26]

Given:

Atul has \dfrac{2}{3} lb of candy.

Jose has \dfrac{3}{5} lb of candy.

Maria has \dfrac{1}{2} lb less than Jose.

To find:

How many more pounds of candy does Atul have than Maria?

Solution:

Since, Maria has \dfrac{1}{2} lb less than Jose, therefore

Maria has = \dfrac{3}{5}-\dfrac{1}{2} lb

Maria has = \dfrac{6-5}{10} lb

Maria has = \dfrac{1}{10} lb

Difference between the candies Atul and Maria have.

Difference = \dfrac{2}{3}-\dfrac{1}{10} lb

Difference = \dfrac{20-3}{30} lb

Difference = \dfrac{17}{30} lb

Therefore,  Atul have \dfrac{17}{30} lb of candy more than Maria.

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3 years ago
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madam [21]

Answer:525

Step-by-step explanation:15•35=525

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7 0
3 years ago
Read 2 more answers
I think it’s the first one, am I correct? <br><br> Explain!
zavuch27 [327]

Answer:

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