Atul has 2/3 lb of candy. Jose has 3/5 lb and Maria has 1/2 lb less then José. How many more pounds of candy does Atul have than

Question

3 years ago

14

Maria? (Show your work please!)

1 answer:

liraira [26] · Answer 1 · 2022-03-07T11:00:28+03:00

Given:

Atul has $\dfrac{2}{3}$ lb of candy.

Jose has $\dfrac{3}{5}$ lb of candy.

Maria has $\dfrac{1}{2}$ lb less than Jose.

To find:

How many more pounds of candy does Atul have than Maria?

Solution:

Since, Maria has $\dfrac{1}{2}$ lb less than Jose, therefore

Maria has = $\dfrac{3}{5}-\dfrac{1}{2}$ lb

Maria has = $\dfrac{6-5}{10}$ lb

Maria has = $\dfrac{1}{10}$ lb

Difference between the candies Atul and Maria have.

Difference = $\dfrac{2}{3}-\dfrac{1}{10}$ lb

Difference = $\dfrac{20-3}{30}$ lb

Difference = $\dfrac{17}{30}$ lb

Therefore, Atul have $\dfrac{17}{30}$ lb of candy more than Maria.