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kykrilka [37]
3 years ago
11

timf 3 số tự nhiên lẻ liên tiếp, biết tích của hai số lớn nhất lớn hơn 6 lần số bé nhất là 177 đơn vị

Mathematics
1 answer:
Murljashka [212]3 years ago
7 0

Answer:

13, 15, 17

Step-by-step explanation:

Gọi 3 STN lẻ cần tìm là a, a+2, a+4 (a thuộc N*)

Theo đề bài ta có:

(a + 2)(a + 4) - 177 = 6a

=> a^2 + 4a + 2a + 8 = 6a + 177

=> a^2 + 6a + 8 = 6a + 177

=> a^2 + 6a - 6a = 177 - 8 (chuyển vế)

=> a^2 = 169 = 13^2

=> a = 13

=> a+2 = 15, a+4 = 17

Vậy 3 STN lẻ cần tìm là 13, 15, 17

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