The midpoints are (8,3) and (6.5,6).
<u>Step-by-step explanation</u>:
Midpoint formula = ((x1+x2)/2 , (y1+y2)/2)
(x1,y1) = (5,2)
(x2,y2) = (11,4)
Midpoint = ((5+11)/2 , (2+4)/2)
⇒ ((16/2) , (6/2))
⇒ (8,3)
(x1,y1) = (3,8)
(x2,y2) = (10,4)
Midpoint = ((3+10)/2 , (8+4)/2)
⇒ ((13/2) , (12/2))
⇒ (6.5,6)
Answer:
Step-by-step explanation:
12
This is what we call a 45-45 traingle
This means that the lengths of the two non-hyptonouse lengths are the same
luckily we're given that it's 6√2
We can then use the pathagaryem theory to solve for the last side
we have
(6√2)²+(6√2)²=x²
Put this into your calculator and get
144= x²
x = 12
Answer:
So, I don't quite have the answer, but I believe you just turn that into an improper fraction and divide it by 8 classes? Decimal Answer.
Step-by-step explanation:
Answer:
a + b = 5.30
a + b = 7
No
Step-by-step explanation:
Expressing the information as system of linear equation :
Let apples = a, oranges = b
If $5.30 is charged for one apple and one orange, then we have ;
a + b = 5.30 - - - (1)
If $14 is charged for 2 apples and 2 oranges, then we have ;
2a + 2b = 14 - - - - (2)
a + b = 7
Since both equations gives varying combined cost for equal amount of the fruit, then a unique cost cannot be obtained for each fruit from the systems of equation using simultaneous equation process.
From (1)
a = 5.30 - b
Put a = 5.30 - b in (2)
2(5.30 - b) + 2b = 14
10.6 - 2b + 2b = 14
10.6 = 14 - - - - - (variables cancels out).
