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Anna007 [38]
3 years ago
8

(a) On a normal distribution of exam scores, Poindexter scored at the 10th

Mathematics
1 answer:
enot [183]3 years ago
5 0

Answer:

Step-by-step explanation:

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Find the slope (14,7), (10, 2)​
CaHeK987 [17]
5/4 because you use y2-y1 over x2-x1
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3 years ago
Julio says, "If you subtract 18 from my number and multiply the difference by - 3, the result is
ololo11 [35]

Answer:

(X-18)-3=15

3x-54=15

3x=15+54

3x=69

x=23

So jubo's number is 23

3 0
3 years ago
I WILL MARK BRAINLIEST!!!!!!!!!
Lubov Fominskaja [6]

Answer:

It is not

Step-by-step explanation:

It is not because this is an exponential function

y=x^2

1^2=1

2^2=4

3^2=9

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7 0
3 years ago
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pishuonlain [190]

Answer:

x = 3

Step-by-step explanation:

Because the endpoints of the segment with length 12.5 are the midpoints of the sides of the large trapezoid, the length of that segments, 12.5, is the average of the lengths of the top and bottom lengths of the large trapezoid.

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Multiply both sides by 2.

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3 0
3 years ago
Find the smallest sample size n that will guarantee at least a 90% chance of the sample mean income being within $500 of the pop
Andreyy89

Answer:

The smallest sample size n that will guarantee at least a 90% chance of the sample mean income being within $500 of the population mean income is 48.

Step-by-step explanation:

The complete question is:

The mean salary of people living in a certain city is $37,500 with a standard deviation of $2,103. A sample of n people will be selected at random from those living in the city. Find the smallest sample size n that will guarantee at least a 90% chance of the sample mean income being within $500 of the population mean income. Round your answer up to the next largest whole number.

Solution:

The (1 - <em>α</em>)% confidence interval for population mean is:

CI=\bar x\pm z_{\alpha/2}\cdot\frac{\sigma}{\sqrt{n}}

The margin of error for this interval is:

MOE=z_{\alpha/2}\cdot\frac{\sigma}{\sqrt{n}}

The critical value of <em>z</em> for 90% confidence level is:

<em>z</em> = 1.645

Compute the required sample size as follows:

MOE=z_{\alpha/2}\cdot\frac{\sigma}{\sqrt{n}}

      n=[\frac{z_{\alpha/2}\cdot\sigma}{MOE}]^{2}\\\\=[\frac{1.645\times 2103}{500}]^{2}\\\\=47.8707620769\\\\\approx 48

Thus, the smallest sample size n that will guarantee at least a 90% chance of the sample mean income being within $500 of the population mean income is 48.

3 0
3 years ago
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