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Misha Larkins [42]
3 years ago
13

What is 9.75 times 3

Mathematics
1 answer:
astra-53 [7]3 years ago
7 0

Step-by-step explanation:

please mark me as brainlest

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What is the average rate of change for h(t) between t=0 and t=2
nordsb [41]

Part a: Option D 18 feet per second

Part b: increasing

Solution:

Height h(t)=-16 t^{2}+50 t+3

Part a: To find the average rate of change for h(t) between t = 0 and t = 2.

Substitute t = 0 in h(t).

h(0)=-16 (0)^{2}+50 (0)+3

h(0) = 3

Substitute t = 2 in h(t).

h(2)=-16 (2)^{2}+50 (2)+3  

h(2) = 39

Average rate of change formula:

           $=\frac{h(b)-h(a)}{b-a}

Here, a = 0 and b = 2.

           $=\frac{h(2)-h(0)}{2-0}

           $=\frac{39-3}{2}

           $=\frac{36}{2}

           = 18

Average rate of change = 18 feet per second

Option D is the correct answer.

Part b:

This means height of the ball is increasing for 0 < x < 2.

6 0
3 years ago
Plz help me i need help
natali 33 [55]
Ok so you know the first garden needs 1 and 2/5 bags of soil. Now first we need to find one fifth of that. So let's make this mied number into an improper fraction:

1 2/5 = 7/5

Ok now let's divide 7/5 by 5:

7/5 divided by 5/1 = 7/25

So Jared will need 7/25 bags of soil for his second garden, but we're STILL not done. now we have to add for the TOTAL.

1 2/5 + 7/25 > 7/5 + 7/25 > 7 x 5 = 35    > 35/25 + 7/25 = 42/25
                                           _________  
                                            5x 5 = 25

Now let's simplify it to 1 and 17/25

8 0
3 years ago
30 points!
madreJ [45]
You would start at (0,36) and then move to (1, 24) , (2,12), (3,0) because he gives out 12 bags per hour 
7 0
3 years ago
Read 2 more answers
The load that can be supported by a rectangular beam varies jointly as the width of the beam and the square of itsâ height, and
storchak [24]

The question is incomplete.Here is the complete question.

The load that can be supported by a rectangular beam varies jointly as the width of the beam and the square of its length, and inversely as the length of the beam. A beam 13 feet long, with a width of 6 inches and a height of 4 inches can support a maximum load of 800 pounds. If a similar board has a width of 8 inches and a height of 7 inches, how long must it be to support 1300 pounds?

Answer: It must be 392 inches or approximately 33 feet.

Step-by-step explanation: According to the question, the measures (width, length and height) of a beam and the weight it supports are in a relation of <u>proportionality</u>, i.e., if divided, the result is a constant.

For the first load:

width = 6in

height = 4in

length = 13ft or 156in

weight = 800lbs

Then, constant will be:

\frac{6.4^{2}}{156} k = 800

k=\frac{800.156}{96}

k = 1300

For the similar beam:

\frac{8.7^{2}}{L}1300=1300

L = 49.8

L = 392in or 32.8ft

A similar board will support 1300lbs if it has 392 inches or 32.8 feet long.

6 0
3 years ago
a) At a clearance sale, a large screen television, originally priced at $18000 is discounted by $3600. What is the percent disco
vlabodo [156]

Answer:

18k

Step-by-step explanation:

did math on this a few weeks ago

4 0
2 years ago
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