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GREYUIT [131]
2 years ago
12

There are 3.76 x 10 to the power of 22 atoms in 1 gram of oxygen. How many atoms are there in 600 grams of oxygen? Write your an

swer in scientific notation.
A.BCD x 10 to the power of E
Mathematics
1 answer:
tatiyna2 years ago
3 0

Answer:

<u>2.256 x 10 to the power of 25</u>

Step-by-step explanation:

There are 3.76 x 10 to the power of 22 atoms in 1 gram of oxygen

So, there are x atoms in 600 grams of oxygen

Using the ratio and proportional

So, the number of atoms = 600 * 3.76 x 10 to the power of 22 =

                                          = 6*10^2 * 3.76 * 10^{22}\\=6*3.76 * 10^2*10^{22}\\=22.56 * 10^{24}\\=2.256 * 10 * 10^{24}\\=2.256 * 10^{25}

So, the answer in scientific notation as A.BCD x 10 to the power of E

Will be <u>2.256 x 10 to the power of 25</u>

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<h2 /><h2>Explanation:</h2>

See the complete question in the attached file. In this exercise, we know that Oceanview charges $100 per day plus a one-time fee of $40. This can be represented by the following equation:

Total cost for Oceanview:

c=100d+40

Total cost for Beachside:

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Where:

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So we have to explain what the equation:

110d=100d+40

represents in the context of the problem. We have used substitution in order to get that equation, so <em>this means that at some specific number of days the cost for Oceanview and  Beachside will be the same.</em>

This value was calculated and we get that<em> the cost at the hotels will be the same after 4 days and it will be $440.</em>

<h2>Learn more:</h2>

Linear equations: brainly.com/question/12412678

#LearnWithBrainly

3 0
2 years ago
I wi mark you brainless and give point of this gets completed
Paraphin [41]

Answer:

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2. (x - 7)( x - 8)

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Step-by-step explanation:

I'm so sorry it took this long that made my brain hurt it was worth it

Sorry it took so long..

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5 0
3 years ago
What is the radius of a sphere with a volume of 4.5π cubic centimeters?
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V=(4/3)pir^3
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divide both sides by pi
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times 3/4 both sides
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3 0
2 years ago
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We want to find a polynomial given that we know its roots and a point on the graph.

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