Answer:
The correct answer is x < 2 or x > -2. The graph would be a line between -2 and 2 with an open circle on both.
Step-by-step explanation:
To solve, first solve the equation for the absolute value portion of the equation.
2|x| + 1 < 5
2|x| < 4
|x| < 2
Now since there is an absolute value around it, we have to complete it for the positive and negative versions.
x < 2 OR x > -2
Answer:
it would be 2
Step-by-step explanation:
take the equation and do 8 - 6 and then you get the answer
The slope of the given line is the coefficient of x, 3/5. The slope of the perpendicular line will be the negative reciprocal of that: -1/(3/5) = -5/3.
The point-slope form of the equation for a line of slope m through point (h, k) can be written ...
... y = m(x -h) +k
For your point and the slope found above, this becomes
... y = (-5/3)(x -15) -5
When x=0, this is
... y = (-5/3)(-15) -5 = 20
The y-intercept is 20.
Answer:
t = - 3, t = - 1
Step-by-step explanation:
Given
h(t) = t² + 4t + 3
To find the zeros equate h(t) to zero, that is
t² + 4t + 3 = 0
Consider the factors of the constant term (+ 3) which sum to give the coefficient of the t- term
The factors are + 3 and + 1, since
3 × 1 = 3 and 3 + 1 = 4, thus
t² + 4t + 3 = (t + 3)(t + 1) = 0
Equate each factor to 0 and solve for t
t + 3 = 0 ⇒ t = - 3
t + 1 = 0 ⇒ t = - 1
smaller zero is t = - 3
larger zero is t = - 1