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zepelin [54]
3 years ago
5

The function y = -x - 3 is graphed only over the domain of {x | -8

Mathematics
1 answer:
algol133 years ago
8 0

Answer:

Determine the range of the function graphed above

[ 0,4 ]

[4, infinite)

(-infinite, 4]

[ -4,0 ]

Step-by-step explanation:

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If the smallest angle of a triangle is 20 degrees and it is included between sides of 4 and 7, then (to the nearest tenth) the s
velikii [3]
Hello,
Al 'Kashi theorem says:

a²=4²+7²-2*4*7*cos 20°=12.37721...
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3 years ago
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Slips of paper numbered 1 to 15 are placed in a box. A slip of paper is drawn at random. What is the probability that the number
monitta

Given:

Slips of paper numbered 1 to 15 are placed in a box.

To find:

The probability that the number picked is either a multiple of 5 or an odd number.

Solution:

We have,

Total outcomes = 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15

No. of total outcomes = 15

Multiple of 5 are 5, 10, 15.

Odd numbers are 1, 3, 5, 7, 9, 11, 13, 15.

Number that are either a multiple of 5 or an odd number are 1, 3, 5, 7, 9, 10, 11, 13, 15.

No. of favorable outcomes = 9

We know that,

\text{Probability}=\dfrac{\text{Favorable outcomes}}{\text{Total outcomes}}

\text{Probability}=\dfrac{9}{15}

\text{Probability}=\dfrac{3}{5}

\text{Probability}=0.6

Therefore, the  probability that the number picked is either a multiple of 5 or an odd number is 0.6.

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3 years ago
Anyone know how to do this? will give brainlest! if you cant help, have a great day!!!
Aleks04 [339]
M= 2 :) I hope this helped you
4 0
3 years ago
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Answer all parts of number 1 thank you.
Scorpion4ik [409]

Hi!

1.)

a:A u B=

(1.0. - 5. \frac{1}{2} .e)

(The same elements are written once.)

b:A u C

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c:B u C

( - 5 .1.e.0.2)

Note:I used dots to mean commas .

Good work!

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Lamar plans to watch 2 movies each month.write an equation represent the total number of movies n that he will watch I m moths
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Answer:

n=2m

Step by step:

total=rate of movie watching per month times months

n=2 movies per month times 'm' months, so,

n=2m

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3 years ago
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