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3 years ago

What is the best estimate for the area of circle A, in square units? Use the approximation “pie”≈3.14.

Mathematics

2 answers:

amm18123 years ago

7 0

Answer:

153.86 un²

Step-by-step explanation:

Area circle = πr²

Radius is the distance of the center to the edge(perimeter)

Radius = 7

Area circle = 3.14(7)²

Area circle = 3.14 * 49 = 153.86

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8_murik_8 [283]3 years ago

5 0

<h2>Solving for the Area of a Circle</h2><h3>Answer:</h3>

The area of the Circle $A$ is approximately $153.86$

<h3>Step-by-step explanation:</h3>

The area of a circle, $A_{\circ}$ , is calculated by $A_{\circ} = \pi r^2$ . We can see that the distance between point $A$ to any point on the circle is $7$ . This means that $7$ is the radius of the circle.

Solving for $A_{\circ}$ :

$A_{\circ} = \pi r^2 \\ A_{\circ} \approx 3.14(7)^2 \\ A_{\circ} \approx 3.14(49) \\ A_{\circ} \approx 153.86$

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A. 16.0<br> b. 25.0<br> c. 9.0<br> d. 17.3

sveticcg [70]

Answer:

B 25.0 is the right answer

Step-by-step explanation:

8 0

3 years ago

Do bonds reduce the overall risk of an investment portfolio? Let x be a random variable representing annual percent return for t

rjkz [21]

Answer:

COV (all stocks) = 0.55

COV (stocks and bonds) = 0.82

Step-by-step explanation:

Coefficient of Variation is used to measure variability.

It is defined as the ration of standard deviation and the mean.

It can be used to compare variability of two population or two samples.

Formula:

$\text{Coefficient of Variation} = \displaystyle\frac{\text{Standard Deviation}}{\text{Mean}}$

$\text{Standard Deviation} = \sqrt{\displaystyle\frac{\sum (x_i -\bar{x})^2}{n-1}}$

where $x_i$ are data points, $\bar{x}$ is the mean and n is the number of observations.

$Mean = \displaystyle\frac{\text{Sum of all observations}}{\text{Total number of observation}}$

x: 14, 0, 39, 25, 32, 27, 28, 14, 14, 15

$Mean = \frac{208}{10} = 20.8$

$Standard~Deviation = \sqrt{\frac{1169.6}{9} } = 11.39$

$Coefficient~of~Variation = \frac{11.39}{20.8} = 0.55$

y = 6, 2, 29, 17, 26, 17, 17, 2, 3, 5

$Mean = \frac{124}{10} = 12.4$

$Standard~Deviation = \sqrt{\frac{924.4}{9} } = 10.13$

$Coefficient~of~Variation = \frac{10.13}{12.4} = 0.82%$

Since coefficient of variation of x is less compared to y, thus it could be said bonds does not reduce overall risk of an investment portfolio.

6 0

2 years ago

Fing the value of x, -3(2x-9)=3(16-x)

Ksivusya [100]

Answer:

x= -7

Step-by-step explanation:

4 0

2 years ago

Read 2 more answers

Tamara earns 2,050 every month. She spends 65% on the amount that she earns. The rest of the money is equally divided and deposi

victus00 [196]

Answer:

Tamara earns $2,050 each month.

She spends 65% of that, so the amount that she spends is:

S = (65%/100%)*$2,050 = 0.65*$2,050 = $1,332.50

Then the amount that she has left is:

R = $2,050 - $1,332.50 = $717.50

Now she divides that in half, and deposits those amounts in two separate accounts.

She deposits $717.50/2 = $358.75 in each acount.

Then she deposits $358.75 per month, so after x months she has:

x*$358.75 in each of those accounts, so one of the accounts will have more than $2,500 when:

x*$358.75 = $2,500

x = $2,500/$358.75 = 6.96

So after 6.96 moths she will have more than $2,500 in one of her accounts, we can round it to:

After 10 months Tamara has deposited more than 2,500 in one of her accounts.

4 0

3 years ago

The diagram shows a parallelogram.

Firlakuza [10]

Check the picture below.

4 0

2 years ago