The regular price is $4 i.e., $3.6 divided by 0.9 = $4
Answer:
47.14
Step-by-step explanation:
35*16=556.6 848-556.6=291.4
16*1.5=24 291.4/24=12.14
35+12.14=47.14
Out of the total 60 students 18 take Algebra 1 and 20 take Algebra II. 10 take both. So out of the 18 taking algebra 10 are taking Algebra II. If we don't count that 10 because they are already counted in Algebra II count. So 28 students are taking either course. Therefore 60-28 = 32 students who are not taking either of these courses
4y=-16-7x equation 1. substitute equation 1 in given equation. 7x(-16-7x)=-16. -112x-49x=-26
I see this as the difference in their current years is 12, and the difference between the number of years they both age in human years is 3, so after 4 human years they become the same age.
