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Marat540 [252]
2 years ago
12

What is the perimeter of the figure below. Round to the nearest tenth.

Mathematics
1 answer:
Oksi-84 [34.3K]2 years ago
5 0

Answer:

The perimeter value is 39.047 or 39.0

Step-by-step explanation:

I. When perimetaer value = A + B + C + D + E

Find A, B, C, D and E value

A = c sq = a sq + b sq

   = 8 sq + 5 sq

   = 64 + 25

c qr = 89

A = 9.433

B = 8 sq + 6 sq

  = 64 + 36

  = 100

B = 10

C = 6

D = 6 sq + 4 sq

  = 36 + 16

  = 52

D = 7.211

E = 5 sq + 4 sq

  = 25 + 16

  = 41

E = 6.403

So A + B + C + D + E = 9.433 + 10 + 6 + 7.211 + 6.403

= 39.047 or 39.0

Hope that help :)

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This is simple. Coordinate form is (x,y) so you would just plug in your values. 

2(5)-(1)=11

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7 0
3 years ago
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Give coordinates of the point where x = 3. Explain what the point represents in this situation:
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Answer:

if x=3 then y is o

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4 0
3 years ago
A line m is perpendicular to an angle bisector of ∠A. The sides of ∠A intersect this line m at points M and N. Prove that △AMN i
Ray Of Light [21]

Answer:


Step-by-step explanation:

<em><u>Given</u></em><u>:</u>       A line m is perpendicular to the angle bisector of ∠A. We call this  

                 intersecting point as D. Hence, in figure ∠ADM=∠ADN =90°.

                 AD is angle bisector of ∠A. Hence, ∠MAD=∠NAD.

<u><em>To Prove</em></u>:   <em><u>ΔAMN is an isosceles triangle. i.e any two sides in ΔAMN are</u></em>

<em>                    </em><em><u>equal. </u></em>

<em><u>Solution</u></em>:  Now, In ΔADM and ΔADN

                 ∠MAD=∠NAD     ...(1) (∵Given)

                  AD=AD                ...(2) (∵common side)

                  ∠ADM=∠ADN     ...(3) (∵Given)

                  <u><em> Hence, from equation (1),(2),(3) ΔADM ≅ ΔADN</em></u>

                                                         ( ∵ ASA  congruence rule)

                  ⇒<u><em> AM=AN</em></u>

                  Now, In Δ AMN

                 AM=AN (∵ Proved)

                  Hence, ΔAMN is an isosceles  triangle.


7 0
3 years ago
A rectangular picture frame measures 63 cm by 63 cm. What is the perimeter or distance around the picture frame in meters? m
Natalija [7]
Hi!

We need the perimeter in meters, so we have to turn cm into m. 
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The perimeter is the sum of all side measures:
P = 0.63 + 0.63 + 0.63 + 0.63
P = 4 * 0.63
P = 2.52 m

;)
6 0
3 years ago
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