Question

A patient is given 200 mg of a drug with the formula: C32H34N6O10. How many mg of the drug is carbon?

Answer 1

200 mg of C₃₂H₃₄N₆O₁₀ contains 116 mg of carbon.

To obtain the answer to the question, we'll begin by calculating the molar mass of C₃₂H₃₄N₆O₁₀. This can be obtained as follow:

Molar mass of C₃₂H₃₄N₆O₁₀ = (12×32) + (1×34) + (14×6) + (16×10)

= 384 + 34 + 84 + 160

= 662 g/mol

From the molar mass of C₃₂H₃₄N₆O₁₀, we can see that:

662 g of C₃₂H₃₄N₆O₁₀ contains 384 g of carbon.

Converting 662 g of C₃₂H₃₄N₆O₁₀ to mg, we have

1 g = 1000 mg

Therefore,

662 g = 662 × 1000

662 g of C₃₂H₃₄N₆O₁₀ = 662000 mg

Converting 384 g of carbon to mg, we have,

1 g = 1000 mg

Therefore,

384 g = 384 × 1000

384 g of carbon = 384000 mg

Thus, we can say that:

662000 mg of C₃₂H₃₄N₆O₁₀ contains 384000 mg of carbon.

Finally, we shall determine the mass (in mg) of carbon in 200 mg of C₃₂H₃₄N₆O₁₀. This can be obtained as follow:

662000 mg of C₃₂H₃₄N₆O₁₀ contains 384000 mg of carbon.

Therefore, 200 mg of C₃₂H₃₄N₆O₁₀ will contain = $\frac{200 * 384000}{662000}$ = 116 mg of carbon.

Thus, we can conclude that 200 mg of C₃₂H₃₄N₆O₁₀ contains 116 mg of carbon.

Learn more: brainly.com/question/24572517