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fenix001 [56]
3 years ago
9

Which interaction produces dispersive forces by creating temporary dipoles that induce dipoles in other molecules?

Chemistry
1 answer:
Tpy6a [65]3 years ago
5 0
This interaction must be one of the intermolecular forces, particularly, Van der Waals forces. From the description given, this force is called <em>induced dipole-induced dipole forces</em>. Dipole is defined as the separation of positive and negative charges. This type of intermolecular force is very weak compared to hydrogen bonding.
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Which of the following have the most similar properties?
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Compare gases with liquids and solids according to the kinetic molecular theory
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8 0
3 years ago
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Gaseous compound Q contains only xenon and oxygen. When 0.100 gg of Q is placed in a 50.0 mLmL steel vessel at 0 ∘C∘C, the press
asambeis [7]

The question is incomplete, here is the complete question:

Gaseous compound Q contains only xenon and oxygen. When a 0.100 g sample of Q is placed in a 50.0-mL steel vessel at 0°C, the pressure is 0.229 atm. What is the likely formula of the compound?

A. XeO

B. XeO_4

C. Xe_2O_2  

D. Xe_2O_3

E. Xe_3O_2

<u>Answer:</u> The chemical formula of the compound is XeO_4

<u>Explanation:</u>

To calculate the molecular mass of the compound, we use the equation given by ideal gas equation:

PV = nRT

Or,

PV=\frac{w}{M}RT

where,

P = Pressure of the gas = 0.229 atm

V = Volume of the gas  = 50.0 mL = 0.050 L     (Conversion factor:  1 L = 1000 mL)

w = Weight of the gas = 0.100 g

M = Molar mass of gas  = ?

R = Gas constant = 0.0821\text{ L atm }mol^{-1}K^{-1}

T = Temperature of the gas = 0^oC=273K

Putting value in above equation, we get:

0.229\times 0.050=\frac{0.100}{M}\times 0.0821\times 273\\\\M=\frac{0.100\times 0.0821\times 273}{0.229\times 0.050}=195.4g/mol\approx 195g/mol

The compound having mass as 195 g/mol is XeO_4

Hence, the chemical formula of the compound is XeO_4

5 0
3 years ago
Which of the following is a mixture <br><br> Water<br><br> Ink<br><br> Alcohol <br><br> Mercury
Zepler [3.9K]
Paper chromatography can be applied to "ink" to determine if it is a pure substance or a "mixture" of pure substances (in which two or more pure substances are combined). Since, tested with paper chromatography, "ink" separates into its constituent pure substances, Ink is a mixture.

I hope this helps.

P.S. Thank you for choosing me as brainliest answer on my last.
4 0
4 years ago
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