Answer: the answer is attached
Step-by-step explanation:
2y/y-3. 4y-12/2y+6
The work done by the gas when the gas expands will be 567.65 ft-lb.
<h3>What is the work done for an isothermal process?</h3>
The Pressure is inversely proportional to the volume.
Let the initial pressure and initial volume be P₁ and V₁, and the final volume be V₂.
Then the work done by the gas will be
WD = P₁ V₁ ln (V₂ / V₁)
A quantity of the gas with an initial volume of 2 cubic feet and an initial pressure of 700 pounds per square foot.
The gas expands to a volume of 3 cubic feet.
Then the work done by the gas will be
WD = 700 x 2 x ln (3/2)
WD = 1400 x 0.405
WD = 567.65 ft-lb
The work done by the gas when the gas expands will be 567.65 ft-lb.
More about the work done for isothermal process link is given below.
brainly.com/question/4218306
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The answer you are looking for is 339
Answer:
n = 2
Step-by-step explanation:
Expand the brackets.
1/2n - 2 - 3 = 3 - 2n - 3
Add or subtract terms.
1/2n - 5 = -2n
Add 5 and 2n on both sides.
1/2n + 2n = 5
5/2n = 5
Multiply both sides by 2/5.
n = 5 × 2/5
n = 10/5
n = 2
4 is the only factor common among all terms
