Answer:
No
Step-by-step explanation:
If the projectile lands at the same height it was launched from, then its time of flight will be proportional to the vertical speed. Its horizontal distance will be the product of its horizontal speed and its time of flight, so will be proportional to the square of the velocity.
If the velocity is doubled, the projectile can be expected to travel 2² = 4 times as far, not twice as far.
Answer:
The answer would be C. An obtuse equilateral triangle :)
Answer:
3/1/4
That's the expression represents Lena's speed in miles per hour
To classify the angle of a triangle (acute, obtuse, or right), you can use slope formula to see if the slopes are perpendicular. If so, it is a right triangle. The distance formula can be applied to figure out whether the triangle is isosceles, equilateral, or scalene. if the triangle is isosceles, then two of the sides will be the same length and one side will be of a different length. If the triangle is equilateral, then all sides will be of the same length. If the triangle is scalene, then all side will be of different lengths.
Answer:
![d = \sqrt[2]{34}](https://tex.z-dn.net/?f=d%20%3D%20%5Csqrt%5B2%5D%7B34%7D)
Step-by-step explanation:
We are solving for the segment of AB. Note that it is a line segment, so there will be end points, those being A(-4, 5) & B(2, -5).
Use the following distance formula:
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Let:
Point B(2 , -5) = (x₁ , y₁)
Point A(-4 , 5) = (x₂ , y₂)
Plug in the corresponding numbers to the corresponding variables.
Simplify. Remember to follow PEMDAS. First, solve the parenthesis, then the powers, then add, and then finally square root.
Simplify:
![d = \sqrt{136} = \sqrt{2 * 2 * 2 * 17} = \sqrt[2]{17 * 2} = \sqrt[2]{34}](https://tex.z-dn.net/?f=d%20%3D%20%5Csqrt%7B136%7D%20%3D%20%5Csqrt%7B2%20%2A%202%20%2A%202%20%2A%2017%7D%20%20%3D%20%5Csqrt%5B2%5D%7B17%20%2A%202%7D%20%3D%20%5Csqrt%5B2%5D%7B34%7D)
is your answer.
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