Question

Can anyone please help I’ve been working on this one for awhile

Answer 1

The diagram shows that angle AQB = angle BQC
So 5x= 8x-24
3x= 24
x=8 (first answer)


AQB= 5(8) = 40 (second answer)


BQC= 8(8)-24 = 64-24 = 40 ( third answer)



AQC = AQB+ BQC
AQC= 40+40 = 80 (Fourth answer)


(Mark me the brainliest if this has helped)

Answer 2

Answer:

x=8

<AQB= 40

<BQC=40

Therefore AQC = 40 + 40 = 80

Step-by-step explanation:

If QB is the angle Bisector of < AQC

Then, <AQB=<BQC (Reason: The angle bisector divides an angle in equal measurement)

So,

5x= 8x-24

24 = 8x - 5x

24= 3x

24 /3 = x

Therefore, x = 8

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Then lets substitute

<AQB =5 x

5 ×8 = 40

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<BCQ = 8x - 24

8×8-24

64-24= 40

(the angle AQB and angle BQC are equal)

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Then <AQC= 40 +40 = 80

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FINISH

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