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kozerog [31]
3 years ago
10

Can anyone please help I’ve been working on this one for awhile

Mathematics
2 answers:
Karo-lina-s [1.5K]3 years ago
7 0
The diagram shows that angle AQB = angle BQC
So 5x= 8x-24
3x= 24
x=8 (first answer)


AQB= 5(8) = 40 (second answer)


BQC= 8(8)-24 = 64-24 = 40 ( third answer)



AQC = AQB+ BQC
AQC= 40+40 = 80 (Fourth answer)


(Mark me the brainliest if this has helped)
Usimov [2.4K]3 years ago
7 0

Answer:

x=8

<AQB= 40

<BQC=40

Therefore AQC = 40 + 40 = 80

Step-by-step explanation:

If QB is the angle Bisector of < AQC

Then, <AQB=<BQC (Reason: The angle bisector divides an angle in equal measurement)

So,

5x= 8x-24

24 = 8x - 5x

24= 3x

24 /3 = x

Therefore, x = 8

---------

Then lets substitute

<AQB =5 x

5 ×8 = 40

--

<BCQ = 8x - 24

8×8-24

64-24= 40

(the angle AQB and angle BQC are equal)

-----

Then <AQC= 40 +40 = 80

--

FINISH

---

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What is m∠PTR? a. 12 b. 40 c. 50 d. 140 HELP!!!
kramer

Answer:

m<PTR = 140°

Step-by-step explanation:

First, find the value of x. To find the value of x, derive an equation which you'd use in solving for x.

m<PTQ = (x + 28)°

m<RTS = (2x + 16)°

m<PTQ = m<RTS (vertical opposite angles are congruent)

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x + 28 = 2x + 16

Solve for x. Combine like terms

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12 = x

x = 12

Find m<PTQ

m<PTQ = (x + 28)

plug in the value of x

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m<PTR = 180 - 40 (subtracting 40 from each side)

m<PTR = 140°

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