Can anyone please help I’ve been working on this one for awhile
2 answers:
The diagram shows that angle AQB = angle BQC
So 5x= 8x-24
3x= 24
x=8 (first answer)
AQB= 5(8) = 40 (second answer)
BQC= 8(8)-24 = 64-24 = 40 ( third answer)
AQC = AQB+ BQC
AQC= 40+40 = 80 (Fourth answer)
(Mark me the brainliest if this has helped)
Answer:
x=8
<AQB= 40
<BQC=40
Therefore AQC = 40 + 40 = 80
Step-by-step explanation:
If QB is the angle Bisector of < AQC
Then, <AQB=<BQC (Reason: The angle bisector divides an angle in equal measurement)
So,
5x= 8x-24
24 = 8x - 5x
24= 3x
24 /3 = x
Therefore, x = 8
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Then lets substitute
<AQB =5 x
5 ×8 = 40
--
<BCQ = 8x - 24
8×8-24
64-24= 40
(the angle AQB and angle BQC are equal)
-----
Then <AQC= 40 +40 = 80
--
FINISH
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