<span>The diagonals of a parallelogram bisect each other.
So we just equate the two equations BE and DE
2x^2 - x = x^2 + 6
2x^2 - x - x^2 - 6 = 0
x^2 - x - 6 = 0
This is quadratic eqn. So we obtain.
(x - 3) ( x + 2) = 0
Setting each to 0 and solving for x, we have that x = 3 and x = -2
So we have two possible values for BD.
But Since BE = DE then we can simply double each
If x = 3 BD = 2 (2(3)^2 - 3) = 2 ( 18 - 3) = 30 units
If x = - 2 BD = 2((-2)^2 -3 ) = 2 (8 - 3) = 10 units</span>
The correct answer is -15 because the absolute value is 15 but there is a negative outside the absolute value lines making it negative :)
IF your equation is this: h(t)= -16t^2 + 27t + 7, then you set it equal to 17 and solve for t. What this does is tells you the times (t) when the ball is exactly 17 feet off the ground. Because this is a parabola, the ball will go up past the 17 foot mark, then pass it again on the way back down. This happens at .55 seconds (going up), and 1.13 seconds (coming down).
