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2 years ago

Select the correct order for the following numbers. Numbers should be ordered from smallest to largest.

Mathematics

1 answer:

ss7ja [257]2 years ago

5 0

Answer:

The answer is c, a, b, d

Step-by-step explanation:

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Find the base of a parallelogram with the area of 60 in.² and height of 4 inches use the formula for the area of the parallelogr

Alexxx [7]

A = bh
60 in.² = b(4)
60/4 = b
b = 15 inches

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2 years ago

Which of the following are true of F(x)?

Mama L [17]

You forgot to put the options and the rest of the equation

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2 years ago

A straight line is to a ruler as an angle is to: A. cosine B. two rulers C. protractor D. calculator

Lelechka [254]

Answer:

Protractor

Step-by-step explanation:

You use a ruler to draw a straight line.

You use a protractor to draw an angle.

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3 years ago

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Multiply the following complex numbers (4-6i)(6-8i)

Bad White [126]

(4-6i)(6-8i)

24-32i-36i+48i²

24 + -68i - 48

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3 years ago

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A sailboat is sitting at rest near its dock. A rope attached to the bow of the boat is drawn in over a pulley that stands on a p

irina [24]

Answer:

The boat is approaching the dock at rate of 2.14 ft/s

Step-by-step explanation:

The situation given in the question can be modeled as a triangle, please refer to the attached diagram.

A rope attached to the bow of the boat is drawn in over a pulley that stands on a post on the end of the dock that is 5 feet higher than the bow that means x = 5 ft.

The length of rope from bow to pulley is 13 feet that means y = 13 ft.

We know that Pythagorean theorem is given by

$x^{2} + y^{2} = z^{2}$

Differentiating the above equation with respect to time yields,

$2x\frac{dx}{dt} + 2y\frac{dy}{dt} = 2z\frac{dz}{dt}$

$x\frac{dx}{dt} + y\frac{dy}{dt} = z\frac{dz}{dt}$

dx/dt = 0 since dock height doesn't change

$y\frac{dy}{dt} = z\frac{dz}{dt}$

$\frac{dy}{dt} = \frac{z}{y} \frac{dz}{dt}$

The rope is being pulled in at a rate of 2 feet per second that is dz/dt = 2 ft/s

First we need to find z

z² = (5)² + (13)²

z² = 194

z = √194

z = 13.93 ft

So,

$\frac{dy}{dt} = \frac{z}{y} \frac{dz}{dt}$

$\frac{dy}{dt} = \frac{13.93}{13}(2)$

$\frac{dy}{dt} = 2.14$ $ft/s$

Therefore, the boat is approaching the dock at rate of 2.14 ft/s

8 0

2 years ago