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sergey [27]
3 years ago
14

Please answer with proof please!!!

Mathematics
2 answers:
Nastasia [14]3 years ago
5 0

Answer:

I think its ethier A or C becouse it passes through the 8 hours

Step-by-step explanation:

qwelly [4]3 years ago
3 0
A
Cause it can’t be B cause she’s moving
And if it was D he would be slowing down and C doesn’t match up with the 8hours a day
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What is the difference 14/15 - 5/12 written as a decimal?
stiv31 [10]
14/15 - 5/12 

Common denominator is 60.

\frac{4 * 14}{4 * 15} -  \frac{5 * 5}{5 * 12}

56/60 - 25/60

= 31/60 as fraction.
= 0.516 as decimal.

5 0
3 years ago
Read 2 more answers
How do I do this? <br><br>f(a)=4a+5; Find f(2)
Mariana [72]
F(2)=4(2)+5
f(2)=8+5
f(2)=13
6 0
3 years ago
2. Check the boxes for the following sets that are closed under the given
son4ous [18]

The properties of the mathematical sequence allow us to find that the recurrence term is 1 and the operation for each sequence is

   a) Subtraction

   b) Addition

   c) AdditionSum

   d) in this case we have two possibilities

       * If we move to the right the addition

       * If we move to the left the subtraction

The sequence is a set of elements arranged one after another related by some mathematical relationship. The elements of the sequence are called terms.

The sequences shown can be defined by recurrence relations.

Let's analyze each sequence shown, the ellipsis indicates where the sequence advances.

a) ... -7, -6, -5, -4, -3

We can observe that each term has a difference of one unit; if we subtract 1 from the term to the right, we obtain the following term

        -3 -1 = -4

        -4 -1 = -5

        -7 -1 = -8

Therefore the mathematical operation is the subtraction.

b) 0. \sqrt{1}. \sqrt{4}, \sqrt{9}, \sqrt{16}, \sqrt{25}  ...

In this case we can see more clearly the sequence when writing in this way

      0, \sqrt{1^2}. \sqrt{2^2}, \sqrt{3^2 } . \sqrt{4^2} , \sqrt{5^2}

each term is found by adding 1 to the current term,

      \sqrt{(0+1)^2} = \sqrt{1^2} \\\sqrt{(1+1)^2} = \sqrt{2^2}\\\sqrt{(2+1)^2} = \sqrt{3^2}\\\sqrt{(5+1)^2} = \sqrt{6^2}

Therefore the mathematical operation is the addition

c)   ... \frac{-10}{2}. \frac{-8}{2}, \frac{-6}{2}, \frac{-4}{2}. \frac{-2}{2}. ...

      The recurrence term is unity, with the fact that the sequence extends to the right and to the left the operation is

  • To move to the right add 1

           -\frac{-10}{2} + 1 = \frac{-10}{2}  -   \frac{2}{2}  = \frac{-8}{2}\\\frac{-8}{2} + \frac{2}{2} = \frac{-6}{2}

  • To move left subtract 1

         \frac{-2}{2} - 1 = \frac{-4}{2}\\\frac{-4}{2} - \frac{2}{2} = \frac{-6}{2}

         

Using the properties the mathematical sequence we find that the recurrence term is 1 and the operation for each sequence is

   a) Subtraction

   b) Sum

   c) Sum

   d) This case we have two possibilities

  •  If we move to the right the sum
  •  If we move to the left we subtract

Learn more here: brainly.com/question/4626313

5 0
3 years ago
Worth 20 points
bezimeni [28]

Answer:

1. 1/8 ÷ 3/4 = 1/6

2. 3/5 ÷ 3/2 = 2/5

3. 4/1 ÷ 2/3 = 6

4.9/4 ÷ 6/5 = 15/8

5.22/4 ÷ 2/5 = 261/80

Step-by-step explanation:

Hope this Helped

5 0
3 years ago
6. The table shows the equations Ms. Valez discussed in math class today.
k0ka [10]

Answer:

One zero is always added when the power is added by +1

Step-by-step explanation:

6 0
4 years ago
Read 2 more answers
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