1-Gene
2-Chromosome
3-reproduction
4-I don’t know :(
5-Nucleus
6-Daughter cell
7-I don’t know this one either :(
Answer:
Explanation:
This question is incomplete. However, what is described in this question is a method of DNA damage repair mechanism. The method described is called base excision repair. Generally, glycosylases play important roles in base excision repair (as they detect and remove these damaged bases).
One thing that can be considered while identifying the bond to be broken is the codon that will be formed after the removal of base. If this codon (a three base sequence) will still produce the same protein as when a normal cytosine was present.
NOTE: During this base excision repair, a glycosylase will detect and remove the damaged cytosine. Once removed, the remaining nucleotide backbone (of the removed cytosine) is also removed and the gap is filled and sealed by other enzymes in this repair mechanism.
There’s no picture how do I know which one?
Answer:
D. to allow members to improve their personal lot better than that of
their in-group
Explanation:
I got it right
Good Luck and Have a Blessed Day
We have that for the Question "since ph can affect the activity of the <u>antibiotics</u> why would the Kirby bauer test require that the agar have a ph of 7.4" it can be said that
- Why the Kirby <u>bauer </u>test require that the agar have a ph of 7.4 is because while <em>agents </em>may be in excessive activity, given a scenario that the <em>pH </em>is to exceed 7.4 the results might inverse.
From the question we are told
since ph can <em>affect </em>the activity of the antibiotics why would the Kirby <u>bauer </u>test require that the agar have a ph of 7.4
Generally
Agar has a ph value that should exist between 7.2 and 7.4 within a room temperature,given it solidifies and this should be when initially prepared
Therefore
Why the Kirby <u>bauer </u>test require that the agar have a ph of 7.4 is because
while <em>agents </em>may be in excessive activity, given a scenario that the <em>pH </em>is to exceed 7.4 the results might inverse.
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