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mote1985 [20]
3 years ago
8

Please help me fast!!( It's about writing linear equations from a graph)

Mathematics
2 answers:
Vlad1618 [11]3 years ago
7 0

Answer:

y=-5+x have a good day

Step-by-step explanation:

MatroZZZ [7]3 years ago
4 0
Good luck this is the steps

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What is the surface area of the cube shown?
Kryger [21]

Step-by-step explanation:

solve for surface area

A=6a^2

a=edge

3 0
3 years ago
what number must be added to 3 and 8 so that the ratio of the first number to the second number is equal to 3 :4​
Grace [21]
The answer is 12.
Steps
If that number is x
(3+x)/(8+x)=3/4
"Cross multply"
4(3+x)=3(8+x)
12+4x=24+3x
x=12
To check: add 12 to 3 and 8. 3+12=15 and 8+12=20. 15/20=3/4
3 0
3 years ago
Can someone please help, I'll give brainliest!!! WORTH 40 PTS!
Studentka2010 [4]

Answer:

X = 14.48528137

Step-by-step explanation:

  1. ADD 72 TO BOTH SIDES
  2. SQUARE ROOT 72
  3. ADD 6
  4. X = 14.48528137
5 0
3 years ago
Please help quick will give brainliest
Snowcat [4.5K]

25t means "25 times t" where t is some unknown number. It is a placeholder for a number.

To find what the number is, we undo what is happening to t. So we divide both sides by 25 to undo the operation "multiply by 25"

----------

25*t = 1125

25*t/25 = 1125/25 divide both sides by 25

t = 45

---------

<h3>Answer: 45</h3>

As a check, we can plug t = 45 into the equation and we should get the same value on both sides

25*t = 1125

25*45 = 1125 replace every t with 45

1125 = 1125 the answer is confirmed

5 0
4 years ago
Read 2 more answers
Construct a quadratic polynomial whose zeroes are negatives of the zeroes of the
sp2606 [1]

Given:

The given quadratic polynomial is :

x^2-x-12

To find:

The quadratic polynomial whose zeroes are negatives of the zeroes of the given polynomial.

Solution:

We have,

x^2-x-12

Equate the polynomial with 0 to find the zeroes.

x^2-x-12=0

Splitting the middle term, we get

x^2-4x+3x-12=0

x(x-4)+3(x-4)=0

(x+3)(x-4)=0

x=-3,4

The zeroes of the given polynomial are -3 and 4.

The zeroes of a quadratic polynomial are negatives of the zeroes of the given polynomial. So, the zeroes of the required polynomial are 3 and -4.

A quadratic polynomial is defined as:

x^2-(\text{Sum of zeroes})x+\text{Product of zeroes}

x^2-(3+(-4))x+(3)(-4)

x^2-(-1)x+(-12)

x^2+x-12

Therefore, the required polynomial is x^2+x-12.

4 0
3 years ago
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