Find the probability of rolling two number cubes and getting a 2 on the first number cube and a 6 on the second?
1 answer:
Answer:
A
Step-by-step explanation:
A cube has 6 sides
Only one side of the cube has 2 on it
The probability of getting 2 would be 1/6
Only one side of the cube has 6 on it
The probability of getting 6 would be 1/6
For both events to happen together
1/6 x 1/6 = 1/36
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The answer would be True because the sequence is constant
So 8x3 = 24
24 + 12x
the common factor is 12
so you divide everything by 12
24 ÷ 12 = 2
12x ÷ 12 = x
final answer: 12 (2+x)
Answer:
The two numbers are:
30 and 18
Step-by-step explanation:
a + b = 48
a - b = 12
From the first eq.
a = 48 - b
Replacing this last value in the second eq.
(48 - b) - b = 12
48 - 2b = 12
48 - 12 = 2b
36 = 2b
36/2 = b
18 = b
from the first eq.
a + 18 = 48
a = 48 - 18
a = 30
Check:
from the second eq.
a - b = 12
30 - 18 = 12
Answer:
(x-y)(x+6)
Step-by-step explanation:
x^2+6x-xy-6y
x*(x+6)-y(x+6)
(x-y)(x+6)
Answer: $498.08
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