Answer
20%
Step-by-step explanation:
10.00 is the start wage, 12.00 is the new wage
going from 10 to 12 dollars is a 2 dollar increase
2 dollars is 20% of her original salary, so she is now making 120% of what she previosuly made which is a 20% increase
The intersection of
is 
Explanation:
The expression is 
To determine the intersection of these two inequalities, let us solve the two inequalities separately.
Consider 
Subtracting both sides by 1, we have,
Also, consider 
Adding both sides by 4, we have,

Using these two simplified inequalities in the expression, we have,

Writing this in the interval notation, we get,

Hence, the intersection of the two interval is

Thus, the intersection of
is 
Answer:
a. 19x-13 b. 
Step-by-step explanation:
a. 3(-3+5x)-1(4-4x) = -9+15x-4+4x = 15x+4x-9-4 = 19x-13.
b. 
= 
She should ask her parents how it works before doingt it
Recall your d = rt, distance = rate * time.
b = speed rate of the boat.
c = speed rate of the current.
keeping in mind that, as the boat goes Upstream, against the current, it's speed is not "b", but is really " b - c ", because the current is subtracting speed from it.
likewise, when the boat is going Downstream, because is going with the current, is really going faster at " b + c ".

what is the speed of the boat? well, 61 + c = b.