Which best describes the error in finding the missing length of the triangle?

A certain math textbook is 3/4 of an inch thick. how many of these books will fit on a shelf that is 3 feet wide

Advocard [28]

48 books will fit on this shelf.

6 0

3 years ago

In the figure below, BD and AC are diameters of circle P.

elena-14-01-66 [18.8K]

Answer:

$arc\ DC=30^o$

Step-by-step explanation:

The picture of the question in the attached figure

The point P is the center of the circle (the drawing is not a scale )

step 1

Find the measure of angle ∠CPD

we know that

$m\angle CPD+150^o=180^o$ ---> by supplementary angles (form a linear pair)

$m\angle CPD=180^o-150^o=30^o$

step 2

Find the measure of arc DC

we know that

Central angle is the angle that has its vertex in the center of the circumference and the sides are radii of it

so

$arc\ DC=m\angle CPD$ ----> by central angle

therefore

$arc\ DC=30^o$

5 0

3 years ago

In a sample of 77 children , the mean age as at which they first began to combine words was 16.51 months

astraxan [27]

Answer:

Mean age = 1271.27

Step-by-step explanation:

No of children = 77

The age at which children first began to combine words = 16.51 months

Mean age = No of children × age at which children first began to combine words

= 77 × 16.51

= 1271.27

Mean age = 1271.27

7 0

3 years ago

Write in slope intercept form: (-3,7) and (6,-8)

tiny-mole [99]

Answer: y=-5/3 + 2

Step-by-step explanation:

Hope this helps

5 0

3 years ago

Read 2 more answers

Define z_alpha to be a z-score with an area of alpha to the right. For Example: z_0.10 means P(Z > z_0.10) = 0.10. We would a

Reptile [31]

Answer:

a) P(-z_0.025 < Z < z_0.025)

For this case we want a quantile that accumulates 0.025 of the area on the tails of the normal standard distribution, and for this case we can calculate the z value with the following excel codes:

"=NORM.INV(0.025,0,1)"

And for this case the two values are : $z_{crit}= \pm 1.96$

b) P(-z_{\alpha/2} < Z < z_{\alpha/2})

For this case we want a quantile that accumulates $\alpha/2$ of the area on the tails of the normal standard distribution, and for this case we can calculate the z value with the following excel codes:

"=NORM.INV(alpha/2,0,1)"

c) For this case we want to find a value of z that satisfy:

P(Z > z_alpha) = 0.05.

And we can use the following excel code:

"=NORM.INV(0.95,0,1)"

And we got $z_{\alpha/2}=1.64$

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".

Solution to the problem

Part a

P(-z_0.025 < Z < z_0.025)

For this case we want a quantile that accumulates 0.025 of the area on the tails of the normal standard distribution, and for this case we can calculate the z value with the following excel codes:

"=NORM.INV(0.025,0,1)"

And for this case the two values are : $z_{crit}= \pm 1.96$

Part b

P(-z_{\alpha/2} < Z < z_{\alpha/2})

For this case we want a quantile that accumulates $\alpha/2$ of the area on the tails of the normal standard distribution, and for this case we can calculate the z value with the following excel codes:

"=NORM.INV(alpha/2,0,1)"

Part c

For this case we want to find a value of z that satisfy:

P(Z > z_alpha) = 0.05.

And we can use the following excel code:

"=NORM.INV(0.95,0,1)"

And we got $z_{\alpha/2}=1.64$

6 0

3 years ago