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Elden [556K]
4 years ago
11

Solve for h: v = pi squared multiplied by h h = V multiplied by pi over r squared h = V over pi r squared h = V plus pi r square

d h = V minus pi r squared
Mathematics
2 answers:
alexandr1967 [171]4 years ago
7 0

Hello from MrBillDoesMath

Answer:

See below for steps.

Discussion:

As I understand the problem statement we have a cylinder of height h and radius r. The volume of the cylinder is given by the formaul:

V = (pi * r^2) h

Divide both sides by (pi * r^2):

V\ (pi * r^2)) =     ( (pi * r^2) * h ) \ ((pi * r^2)   =>

V\ (pi * r^2)  = 1 * h = h  as  (pi * r^2)   \ (pi * r^2))

Therefore, h =  V\ (pi * r^2)



Thank you,

Mr. B


Alex787 [66]4 years ago
7 0

Answer:

h=\frac{V}{\pi r^2}

Step-by-step explanation:

We have been given the equation V=\pi r^2h and we have to solve this equation for h.

In order to isolate for h, we have to eliminate \pi r^2 from the right hand side of the equation.

We can see that  \pi r^2 is in multiplication with h in the right hand side. Hence, in order to get rid of this, we can do the opposite operation of multiplication i.e. division.

Hence, divide both sides by  \pi r^2

\frac{V}{\pi r^2}=\frac{\pi r^2h}{\pi r^2}

On simplifying, we get

h=\frac{V}{\pi r^2}

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At Western University the historical mean of scholarship examination scores for freshman applications is 900. A historical popul
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Answer:

a) Null Hypothesis: \mu =900

Alternative hypothesis: \mu \neq 900

b) The 95% confidence interval would be given by (910.05;959.95)    

c) Since we confidence interval not ocntains the value of 900 we fail to reject the null hypothesis that the true mean is 900.

d) z=\frac{935 -900}{\frac{180}{\sqrt{200}}}=2.750

Since is a bilateral test the p value is given by:

p_v =2*P(Z>2.750)=0.0059

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a. State the hypotheses.

On this case we want to check the following system of hypothesis:

Null Hypothesis: \mu =900

Alternative hypothesis: \mu \neq 900

b. What is the 95% confidence interval estimate of the population mean examination  score if a sample of 200 applications provided a sample mean x¯¯¯= 935?

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

\bar X=935 represent the sample mean for the sample  

\mu population mean (variable of interest)

\sigma=180 represent the population standard deviation

n=200 represent the sample size  

The confidence interval for the mean is given by the following formula:

\bar X \pm z_{\alpha/2}\frac{\sigma}{\sqrt{n}}   (1)

In order to calculate the mean and the sample deviation we can use the following formulas:  

\bar X= \sum_{i=1}^n \frac{x_i}{n} (2)  

s=\sqrt{\frac{\sum_{i=1}^n (x_i-\bar X)}{n-1}} (3)  

The mean calculated for this case is \bar X=3278.222

The sample deviation calculated s=97.054

Since the Confidence is 0.95 or 95%, the value of \alpha=0.05 and \alpha/2 =0.025, and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-NORM.INV(0.025,0,1)".And we see that z_{\alpha/2}=1.96

Now we have everything in order to replace into formula (1):

935-1.96\frac{180}{\sqrt{200}}=910.05    

935+1.96\frac{180}{\sqrt{200}}=959.95    

So on this case the 95% confidence interval would be given by (910.05;959.95)    

c. Use the confidence interval to conduct a hypothesis test. Using α= .05, what is your  conclusion?

Since we confidence interval not ocntains the value of 900 we fail to reject the null hypothesis that the true mean is 900.

d. What is the p-value?

The statistic is given by:

z=\frac{\bar X -\mu}{\frac{\sigma}{\sqrt{n}}}

If we replace we got:

z=\frac{935 -900}{\frac{180}{\sqrt{200}}}=2.750

Since is a bilateral test the p value is given by:

p_v =2*P(Z>2.750)=0.0059

So then since the p value is less than the significance we can reject the null hypothesis at 5% of significance.

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