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2 years ago

Please help me!! thank you

Mathematics

1 answer:

Mama L [17]2 years ago

6 0

9514 1404 393

Answer:

x = 1/6

Step-by-step explanation:

The relevant rules of exponents are ...

(a^b)/(a^c) = a^(b-c)

(a^b)^c = a^(bc)

The fraction inside parentheses evaluates to ...

3^(3/4 -3/8) = 3^(3/8)

Then the whole expression evaluates to ...

(3^(3/8))^(4/9) = 3^((3/8)(4/9)) = 3^(12/72) = 3^(1/6)

The value of x is 1/6.

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2 years ago

What are three equivalent ratios for 5/45

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$\frac{5}{45}=5:45\ and\ \frac{5}{45}=\frac{5:5}{45:5}=\frac{1}{9}\\\\\frac{5}{45}=\frac{1}{9}\to\boxed{1:9}\\\\\frac{5}{45}=\frac{1}{9}=\frac{1\cdot2}{9\cdot2}=\frac{2}{18}=\boxed{2:18}\\\\\frac{5}{45}=\frac{1}{9}=\frac{1\cdot3}{9\cdot3}=\frac{3}{27}=\boxed{3:27}\\\\\frac{5}{45}=\frac{1}{9}=\frac{1\cdot4}{9\cdot4}=\frac{4}{36}=\boxed{4:36}\\\vdots$

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2 years ago

Consider the function f(x)=−5x−8 and find the following: a) The average rate of change between the points (−1,f(−1)) and (3,f(3)

kipiarov [429]

Answer:

a. -5

b.-5

c.-5

Step-by-step explanation:

In order to find the average rate of change of a function , we divide the change in the output value by the change in the input value.

Generally, the average rate of change (ARC) on an ecuatios between two points (x1,f(x1)) and (x2,f(x2)) is

ARC = [f(x2)-f(x1)]/ (x2-x1)

In case a)

f(-1)= -5*(-1)-8=5-8= -3 f(3)= -5*3-8= -23

Then ARC= (-23-(-3))/(3-(-1))=-20/4=-5

In case b)

f(a)= (-5a-8)

f(b)= (-5b-8)

Then ARC= [(-5b-8)-(-5a-8)]/(b-a)= (-5b+5a)/(b-a)= -5(b-a)/(b-a)= -5

In case c)

f(x)= -5x-8

f(x+h)= -5(x+h)-8= -5x-5h-8

then ARC= [(-5x-5h-8)-(-5x-8)]/(x+h-x) =-5h/h= -5

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