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Agata [3.3K]
3 years ago
6

Jack was drinking a glass of water near his computer when his dog bumped his arm, spilling water on his keyboard. What is the fi

rst thing Jack should do?
1. Let the water dry on its own.
2. Put the keyboard outside in the sun to dry.
3. Place the keyboard in rice.
4. Use a microfiber cloth to soak up the excess water.
Computers and Technology
2 answers:
GREYUIT [131]3 years ago
4 0
4. because you dry it, then you put it in rice.
Anvisha [2.4K]3 years ago
3 0

Answer:

4no. is the answer may be

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No, still wash hands

Explanation:

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What determines WiFi speeds, please list all your answers and explain how it affects the WiFi speed.
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8 0
3 years ago
Write the simplest statement that prints the following on a single line: 3 2 1 Go! Note: Whitespace (blank spaces / blank lines)
Olin [163]

Answer:

//here is the statement in java.

import java.util.*;

//class definition

class Solution

{

// main method of the class

public static void main (String[] args) throws java.lang.Exception

{

   try{

    // this statement will print the 3 2 1 Go! and go to newline

       System.out.println("3 2 1 Go!");

   }catch(Exception ex){

       return;}

}

}

Explanation:

We can use "System.out.println()" to print the required output same as it required. After printing this, it will go to newline.

Output:

3 2 1 Go!

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7 0
3 years ago
Write a program with 2 separate functions which compute the GCD (Greatest Common Denominator) and the LCM (Lowest Common Multipl
Maru [420]

Answer:

The program written in Python is as follows

def GCD(num1, num2):

    small = num1

    if num1 > num2:

         small = num2

    for i in range(1, small+1):

         if((num1 % i == 0) and (num2 % i == 0)):

              gcd = i

    print("The GCD is "+ str(gcd))

def LCM(num1,num2):

    big = num2  

    if num1 > num2:

         big = num1

    while(True):

         if((big % num1 == 0) and (big % num2 == 0)):

              lcm = big

              break

         big = big+1

     print("The LCM is "+ str(lcm))

 print("Enter two numbers: ")

num1 = int(input(": "))

num2 = int(input(": "))

GCD(num1, num2)

LCM(num1, num2)

Explanation:

This line defines the GCD function

def GCD(num1, num2):

This line initializes variable small to num1

    small = num1

This line checks if num2 is less than num1, if yes: num2 is assigned to variable small

<em>     if num1 > num2: </em>

<em>          small = num2 </em>

The following iteration determines the GCD of num1 and num2

<em>     for i in range(1, small+1): </em>

<em>          if((num1 % i == 0) and (num2 % i == 0)): </em>

<em>               gcd = i </em>

This line prints the GCD

    print("The GCD is "+ str(gcd))

   

This line defines the LCM function

def LCM(num1,num2):

This line initializes variable big to num2

    big = num2  

This line checks if num1 is greater than num2, if yes: num1 is assigned to variable big

<em>     if num1 > num2: </em>

<em>          big = num1 </em>

The following iteration continues while the LCM has not been gotten.

    while(True):

This if statement determines the LCM using modulo operator

<em>          if((big % num1 == 0) and (big % num2 == 0)): </em>

<em>               lcm = big </em>

<em>               break </em>

<em>          big = big+1 </em>

This line prints the LCM of the two numbers

     print("The LCM is "+ str(lcm))

The main starts here

This line prompts user for two numbers

print("Enter two numbers: ")

The next two lines get user inputs

num1 = int(input(": "))

num2 = int(input(": "))

This calls the GCD function

GCD(num1, num2)

This calls the LCM function

LCM(num1, num2)

<em></em>

<em>See attachment for more structured program</em>

Download txt
5 0
3 years ago
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