1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
gayaneshka [121]
3 years ago
7

One purpose of the dual ignition system on an aircraft engine is to provide for?

Computers and Technology
2 answers:
Reika [66]3 years ago
8 0
Answer: Redundancy

Explanation:
An aircraft is a system that cannot tolerate faults or errors because the consequences can  be fatal.
Therefore the ignition system is an excellent design candidate for redundancy.
Redundancy ensures that if the primary ignition system fails, a reliable backup ignition system will be available.

Another example of redundancy is the use of electric power generators in a hospital. They back up the primary electricity power supply because failure of electric power during surgery cannot be tolerated.
Gnom [1K]3 years ago
7 0
It is done to provide for better engine performance. It is important for two main reasons. One is that if one ignition system fails the other can for a time take care of it and hold its ground until you land or fix it. Another is that it is used for more efficient consumption of fuel and air which makes the engine work better.
You might be interested in
You are studying for a test tomorrow. Your friends invite you to
lapo4ka [179]

Answer: C

Explanation:

7 0
3 years ago
व्याख्या c) Differentiate between Raster Image and Vector Image.​
crimeas [40]

Vector images are described by lines, shapes, and other graphic image components stored in a format that incorporates geometric formulas for rendering the image elements

These are the types of images that are produced when scanning or photographing an object. Raster images are compiled using pixels, or tiny dots, containing unique color and tonal information that come together to create the image.

7 0
3 years ago
Your company has purchased another company that also uses Windows Server 2016 and Active Directory. Both companies need to be ab
Scorpion4ik [409]

Answer:

Create a two-way forest trust

Explanation:

The aim here is to ensure that both companies are able to access the forest resources of each other. The creation of a Two-way Forest Trust would guarantee that as if the Two-way Forest Trust is created between Forest A and Forest B, being the forest resources of the two companies respectively, then all the domains in Forest A will trust every domain in Forest B and vice versa.

5 0
3 years ago
There will be 10 numbers stored contiguously in the computer at location x 7000 . Write a complete LC-3 program, starting at loc
Artist 52 [7]

Answer:

The LC-3 (Little Computer 3) is an ISA definition for a 16-bit computer. Its architecture includes physical memory mapped I/O via a keyboard and display; TRAPs to the operating system for handling service calls; conditional branches on N, Z, and P condition codes; a subroutine call/return mechanism; a minimal set of operation instructions (ADD, AND, and NOT); and various addressing modes for loads and stores (direct, indirect, Base+offset, PC-relative, and an immediate mode for loading effective addresses). Programs written in LC-3 assembler execute out of a 65536 word memory space. All references to memory, from loading instructions to loading and storing register values, pass through the get Mem Adr() function. The hardware/software function of Project 5 is to translate virtual addresses to physical addresses in a restricted memory space. The following is the default, pass-through, MMU code for all memory references by the LC-3 simulator.

unsigned short int get Mem Adr(int va, int rwFlg)

{

unsigned short int pa;

// Warning: Use of system calls that can cause context switches may result in address translation failure

// You should only need to use gittid() once which has already been called for you below. No other syscalls

// are necessary.

TCB* tcb = get TCB();

int task RPT = tcb [gettid()].RPT;

pa = va;

// turn off virtual addressing for system RAM

if (va < 0x3000) return &memory[va];

return &memory[pa];

} // end get MemAdr

Simple OS, Tasks, and the LC-3 Simulator

We introduce into our simple-os a new task that is an lc3 Task. An lc3 Task is a running LC-3 simulator that executes an LC-3 program loaded into the LC-3 memory. The memory for the LC-3 simulator, however, is a single global array. This single global array for memory means that alllc3 Tasks created by the shell use the same memory for their programs. As all LC-3 programs start at address 0x3000 in LC-3, each task overwrites another tasks LC-3 program when the scheduler swaps task. The LC-3 simulator (lc3 Task) invokes the SWAP command every several LC-3 instruction cycles. This swap invocation means the scheduler is going to be swapping LC-3 tasks before the tasks actually complete execution so over writing another LC-3 task's memory in the LC-3 simulator is not a good thing.

You are going to implement virtual memory for the LC-3 simulator so up to 32 LC-3 tasks can be active in the LC-3 simulator memory without corrupting each others data. To implement the virtual memory, we have routed all accesses to LC-3 memory through a get Mem Adr function that is the MMU for the LC-3 simulator. In essence, we now have a single LC-3 simulator with a single unified global memory array yet we provide multi-tasking in the simulator for up to 32 LC-3 programs running in their own private address space using virtual memory.

We are implementing a two level page table for the virtual memory in this programming task. A two level table relies on referring to two page tables both indexed by separate page numbers to complete an address translation from a virtual to a physical address. The first table is referred to as the root page table or RPT for short. The root page table is a fixed static table that always resides in memory. There is exactly one RPT per LC-3 task. Always.

The memory layout for the LC=3 simulator including the system (kernel) area that is always resident and non-paged (i.e., no virtual address translation).

The two figures try to illustrate the situation. The lower figure below demonstrates the use of the two level page table. The RPT resident in non-virtual memory is first referenced to get the address of the second level user page table or (UPT) for short. The right figure in purple and green illustrates the memory layout more precisely. Anything below the address 0x3000 is considered non-virtual. The address space is not paged. The memory in the region 0x2400 through 0x3000 is reserved for the RPTs for up to thirty-two LC-3 tasks. These tables are again always present in memory and are not paged. Accessing any RPT does not require any type of address translation.

The addresses that reside above 0x3000 require an address translation. The memory area is in the virtual address space of the program. This virtual address space means that a UPT belonging to any given task is accessed using a virtual address. You must use the RPT in the system memory to keep track of the correct physical address for the UPT location. Once you have the physical address of the UPT you can complete the address translation by finding the data frame and combining it with the page offset to arrive at your final absolute physical address.

A Two-level page table for virtual memory management.

x7000 123F x7000 0042

x7001 6534 x7001 6534

x7002 300F x7002 300F

x7003 4005 after the program is run, memory x7003 4005

x7004 3F19

7 0
3 years ago
Read 2 more answers
Write a program that calculates and displays the amount ofmoney available in a bank account that initially has $8000 deposited i
Leviafan [203]

Answer:

Written in Python

import math

principal = 8000

rate = 0.025

for i in range(1, 11):

    amount = principal + principal * rate

    principal = amount

    print("Year "+str(i)+": "+str(round(amount,2)))

Explanation:

This line imports math library

import math

This line initializes principal amount to 8000

principal = 8000

This line initializes rate to 0.025

rate = 0.025

The following is an iteration from year 1 to 10

for i in range(1, 11):

    This calculates the amount at the end of the year

    amount = principal + principal * rate

    This calculates the amount at the beginning of the next year

    principal = amount

    This prints the calculated amount

    print("Year "+str(i)+": "+str(round(amount,2)))

6 0
4 years ago
Other questions:
  • "Server Manager will allow you to manage all roles and features installed on any server, and view the status of all your servers
    7·1 answer
  • Help me out for this one
    12·1 answer
  • Which should you use to find a saved file?
    15·2 answers
  • ________ are used in input, processing, and output operations that can help create more efficient programs as the data can be pr
    11·1 answer
  • To support continuous improvement efforts in the workplace, you increase the number of tasks that an employee performs and have
    7·1 answer
  • Write a MARIE program to calculate some basic statistics on a list of positive numbers. The program will ask users to input the
    6·1 answer
  • Why would an online survey of 2,000 visitors to your college’s Web site be of little use in assessing the neighboring community’
    7·1 answer
  • In chapter 3, we discussed syntax and semantics, in general there are two types of grammars for programming languages, regular a
    14·1 answer
  • | HELP PLS! C++ Sorting arrays can be performed using either Selection Sort or Insertion Sort or
    13·1 answer
  • A user can add color to a database to highlight a modification. To do this with a macro, which command screen would you access o
    9·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!