<h2>Solving Equations with Absolute Expressions</h2><h3>
Answer:</h3>
<u>No Solutions</u>
<h3>
Step-by-step explanation:</h3>
Given:

Rewriting the given equation:

We have to realize that the right side of the equation,
, will always be positive no matter what real values of
(because we're taking the absolute value of the expression) and we are equating it to a <em>negative</em> constant number,
. Something that is always positive will never be negative so there's no value for
that satisfies the solution.

<em>You</em><em> </em><em>may</em><em> </em><em>not</em><em> </em><em>read</em><em> </em><em>the</em><em> </em><em>following</em><em> passage</em><em> </em><em>that</em><em> </em><em>I</em><em> </em><em>have</em><em> </em><em>written.</em>

Solving by positive of the expression:

Solving by the negative of the expression:

Checking: 

is an extraneous solution.
Checking: 

is an extraneous solution.