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3 years ago

X+8=-15 help again sorryyy

1 answer:

8 0

X by its self is always 1x

1x+8=-15 you have to get rid of 8 by subtracting on both sides

1x=-23 now get rid of 1 by dividing on both sides

x=-23

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Based on the graph, what is the initial value of the linear relationship?

alex41 [277]

Answer: two over three

Step-by-step explanation:

$y=ax+b$

line intercepts y at (0,-2)

Therefore, $y=ax-2$

Substitute x = 3 in y =ax-2

$y=3a-2$

To find the x-intercept, y = 0

$3a-2=0\\3a=2\\a=\frac{2}{3}$

The slope is 2/3

y-intercept is -2

So two over three

4 0

3 years ago

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Keith_Richards [23]

Answer:

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7 0

3 years ago

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Nataly_w [17]

Answer:

Step-by-step explanation:

4 0

2 years ago

Read 2 more answers

If the perimeter of square region S and the perimeter of rectangular region R are equal and the sides of R are in the ratio 2:3

horrorfan [7]

Answer: The correct option is (B) 24 : 25.

Step-by-step explanation: Given that the perimeter of square region S and the perimeter of rectangular region R are equal and the sides of R are in the ratio 2 : 3.

We are to find the ratio of the area of R to the area of S.

Let 2x, 3x be the sides of rectangle R and y be the side of square S.

Then, according to the given information, we have

$\textup{Perimeter of rectangle R}=\textup{Perimeter of square S}\\\\\Rightarrow2(2x+3x)=2(y+y)\\\\\Rightarrow 5x=2y\\\\\Rightarrow \dfrac{x}{y}=\dfrac{2}{5}~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~(i)$

Therefore, the ratio of the area of R to the area of S is

$\dfrac{2x\times3x}{y\times y}\\\\\\=\dfrac{5x^2}{y^2}\\\\\\=6\left(\dfrac{x}{y}\right)^2\\\\\\=6\times\left(\dfrac{2}{5}\right)^2~~~~~~~~~~~[\textup{Using equation (i)}]\\\\\\=\dfrac{24}{25}\\\\=24:25.$

Thus, the required ratio of the area of R to the area of S is 24 : 25.

Option (B) is CORRECT.

6 0

3 years ago

When v=5 and m=-4, evaluate: 4v2-m2

lions [1.4K]

Answer:

Step-by-step explanation:

4v^2 - m^2

let v=5 and m=-4

4 * (5)^2 - (-4)^2

4* (25) - (16)

100 - 16

8 0

3 years ago