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4 years ago

The width of a rectangle is 3ft less than the length. The perimeter is 62ft. Find the length and width of the rectangle.

Mathematics

1 answer:

Assoli18 [71]4 years ago

8 0

I believe the length of the rectangle is 17 ft and the width is 14

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Megan's room was remodeled. The new area of the room is 175% of the previous area. Only the length of the room changed. part a)

Paraphin [41]

Answer: a) $\frac{175}{100}xy\\\\=1.75xy\\\\$

b) By 0.75 square meters the new area is increased.

Step-by-step explanation:

Let the length of room be l

Let the breadth of room be 'b'

As we know the formula for "Area of rectangle ":

$Area=Length\times breadth\\\\Area=l\times b$

Now, According to question, The new area of the room is 175% of the previous area.

So, a) New area of the room becomes,

$\frac{175}{100}xy\\\\=1.75xy\\\\$

So, it means Length of the room is increased by 175%, because of which the area is increased by 175%.

b) By how many square meters has the area of Megan's room increased

$1.75xy-1xy=0.75\\\\\text{So, by 0.75 square meters the new area is increased.}$

7 0

4 years ago

Meaghan and Lily are dividing 43.61 by 7. Meaghan says that the first digit of the quotient is in the ones place. Lily says it i

Ivahew [28]

Answer: Meaghan is right.

Step-by-step explanation:

For a number like:

123.45

the tens place would be the "2" (second number at the left of the decimal point)

The ones place would be the "3" (first number at the left of the decimal point)

Let's suppose that Lily is correct.

Then the quotient of:

43.61/7

Will be a number with two digits in the left of the decimal point.

The smallest number that meets this condition, is the number 10.

Then let's see:

7*10 = 70

then:

70/7 = 10

and:

43.61 < 70

(70 is larger than 43.61)

then:

43.61/7 < 70/7 = 10

Then:

(43.61/7) < 10

This means that our quotient is smaller than 10, then the first digit of the quotient can not be on the tens place.

Then Meaghan is the correct one.

We also could perform the quotient to find:

43.61/7 = 6.23

So yes, Meaghan is correct.

5 0

3 years ago

Let U = {q, r, s, t, u, v, w, x, y, z} A = {q, s, u, w, y} B = {q, s, y, z} C = {v, w, x, y, z}. List the elements in the set: A

gtnhenbr [62]

Answer:

$A \cup C=\left \{ \text{q, s, u, v, w, x, y, z} \right \}$

Step-by-step explanation:

Given: $\text{U}=\left \{\text{q, r, s, t, u, v, w, x, y, z} \right \}$ , $\text{A}=\left \{\text{q, s, u, w, y} \right \}$ , $\text{B}=\left \{\text{q, s, y, z} \right \}$ ,

$\text{C}=\left \{\text{v, w, x, y, z} \right \}$ .

To find: The elements in the set $A \cup C$ .

Solution:

We have,

$\text{U}=\left \{\text{q, r, s, t, u, v, w, x, y, z} \right \}$

$\text{A}=\left \{\text{q, s, u, w, y} \right \}$

$\text{B}=\left \{\text{q, s, y, z} \right \}$

$\text{C}=\left \{\text{v, w, x, y, z} \right \}$

Now, $A \cup C$ will contain all the elements in the set $A$ and all the elements in set $C$ .

So, $A \cup C=\left \{ \text{q, s, u, v, w, x, y, z} \right \}$ .

Hence, $A \cup C=\left \{ \text{q, s, u, v, w, x, y, z} \right \}$ .

7 0

3 years ago

Read carefully. 5th grade math math. correct answer will be marked brainliest.

Fed [463]

Step-by-step explanation:

I think so

.................

6 0

3 years ago

How to estimate $3472 ÷ 680 and solve problem

alisha [4.7K]

If you'd estimate the numbers, it would be $3500÷700. Because if you look at the tenths place, if the number is higher than 5, than the first digit goes up.
$3500÷700=5
Im not very good at explaining.

3 0

3 years ago