Answer:
(6,0)
Step-by-step explanation:
The coordinates of the points dividing the line segment in ratio m:n can be calculated as:
Here x1, y1 are the coordinates of first point S (-2, -6) and x2, y2 are the coordinates of second point T(18, 9).
In this case m will be 2 and n will be 3 as the ratio is 2:3
Using all these values we can find the coordinates of point Q
Thus, the coordinates of point Q which divides the line segment ST in ratio of 2:3 are (6,0)
Answer:
Approximately (2, 1)
See image
Step-by-step explanation:
Rearrange each equation so it is ready to be graphed on an x-y-axis (see image) look for the point where the two lines cross. This is the solution for the system of equations.
The area of the base would be found using the area of a triangle formula which is 1/2 x base x height.
The base and height are the two sides perpendicular to each other, which are both 5 inches.
The area of the base = 1/2 x 5 x 5 = 12.5 square inches.
The volume of the triangular prism is the area of the base times the height, which is 4 inches.
Volume of the triangular prism is 12.5 x 4 = 50 cubic inches.
Volume of the triangular prism is 1/3 x area of base x height, which is 7:
Volume of the triangular prism = 1/3 x 12.5 x 7 = 29.17 cubic inches.
Total volume = 29.17 + 50 = 79.17 cubic inches.
Answer:
25 girls
Step-by-step explanation:
Let
x denote number of boys
and
y denote number of girls
According to the statement that total 45 people came,
x+y = 45 => Eqn 1
And total paid amount was 175
So,
5x + 3y = 175 => Eqn 2
For solving, We will use the substitution method
So, from eqn 1
x = 45-y
Putting value of x in eqn 2
5(45-y) +3y = 175
225 - 5y + 3y = 175
-2y+225 = 175
-2y = 175-225
-2y = -50
2y = 50
y = 25
Putting y =25 in eqn 1
x+25 = 45
x = 45 - 25
x = 20
As y= 25
So, 25 girls came to the dance ..
1.Identify the fractions. Using the distributive property, you’ll eventually turn them into integers.
2.For all fractions, find the lowest common multiple (LCM) -- the smallest number that both denominators can fit neatly into. This will allow you to add fractions.
3.Multiply every term in the equation by the LCM.
4.Isolate variables adding or subtracting like terms on both sides of the equals sign.
5.Combine like terms.
6.Solve the equation and simplify, if needed.
