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ddd [48]
2 years ago
12

Hello please help me as this is the last question on my test and then I’m done so it would be great if u can tell me if the answ

er is A, B, C, D, or E

Mathematics
2 answers:
agasfer [191]2 years ago
7 0

Answer:

parallelogram.........

elena55 [62]2 years ago
5 0

Answer:

<em>B) Parallellogram </em>

Step-by-step explanation:

Parallelograms are quadrilaterals where all of the opposite sides are parallel and equal.

Hope this helped, let me know if you need anything else ^-^

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1/2 =2x-1/3<br><br> HELP PLZZZZZZZZ
uranmaximum [27]

Answer:

x = \frac{5}{4}

Step-by-step explanation:

\frac{2x-1}{3} = \frac{1}{2} \\

Here cross - multiplying 3 & 2 gives :-

2(2x-1) = 3

Solving this further gives :-

2(2x-1) = 3\\=> 4x-2 = 3\\=>4x = 3+2\\=> 4x=5\\=> x = \frac{5}{4}

5 0
3 years ago
Read 2 more answers
What is the solution to -4l-2x+6l=-24
Masteriza [31]

Answer:

Step-by-step explanation:

-4|-2x+6|=-24 divide both sides by -4

|-2x+6|=6 rewrite twice

-2x+6=6  and  -2x+6=-6

      -6 -6                -6  -6

    -2x=0              -2x= -12   for both equations divide both by two so...

       x=0                  x=6       then check it

4 0
3 years ago
How do I solve for x since the triangles are similar?
Llana [10]
A line that is parallel to a side and intersects the other two siddes divides the sides proportionally.

Set up the proportion
2/x+1 = x/x+6
Multiply means and extremes
2x+12= x^2+ x
Solve to get your answer.
3 0
3 years ago
A professor at a local university noted that the exam grades of her students were normally distributed with a mean of 73 and a s
Umnica [9.8K]

Answer:

88.51 is the minimum score needed to receive a grade of A.          

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 73

Standard Deviation, σ = 11

We are given that the distribution of exam grades is a bell shaped distribution that is a normal distribution.

Formula:

z_{score} = \displaystyle\frac{x-\mu}{\sigma}

We have to find the value of x such that the probability is 0.0793.

P( X \geq x) = P( z \geq \displaystyle\frac{x - 73}{11})=0.0793  

= 1 -P( z \leq \displaystyle\frac{x - 73}{11})=0.0793  

=P( z \leq \displaystyle\frac{x - 73}{11})=0.9207  

Calculation the value from standard normal z table, we have,  

P(z \leq 1.410) = 0.9207

\displaystyle\frac{x - 73}{11} = 1.410\\x =88.51  

Hence, 88.51 is the minimum score needed to receive a grade of A.

3 0
3 years ago
How do you do this problem?<br><br> Anyone can help me and I will make you a Brainliest
mariarad [96]

Answer:

a

Step-by-step explanation:

6 0
3 years ago
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