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3 years ago

What is the solution to this inequality? (x | x < 7)

Mathematics

1 answer:

VARVARA [1.3K]3 years ago

8 0

Answer: The answer is at the bottom.

Step-by-step explanation:

Write

as a piecewise.

Tap for more steps...

{

≥

−

Solve

when

≥

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≤

√

Solve

−

when

Tap for more steps...

Find the union of the solutions.

√

The result can be shown in multiple forms.

Inequality Form:

√

Interval Notation:

(

−

∞

√

)

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Hey!! what is the value of <br><img src="https://tex.z-dn.net/?f=7%20%7B%7D%5E%7B2%7D%20" id="TexFormula1" title="7 {}^{2} " alt

Nata [24]

Answer:

7² = 49 ans

Step-by-step explanation:

7² == 49 ans .....

6 0

3 years ago

Read 2 more answers

Divide x to the 1 half power divided by x to the 2 sevenths power.

Semenov [28]

Remember some basic rules
$\frac{x^m}{x^n}=x^{m-n}$
and
$x^ \frac{m}{n}= \sqrt[n]{x^m}$

so
$\frac{x^\frac{1}{2}}{x^\frac{2}{7}}=x^{\frac{1}{2}-\frac{2}{7}}$
1/2-2/7=
7/14-4/14=
3/14

$x^{\frac{1}{2}-\frac{2}{7}}=x^{\frac{3}{14}}$

$x^ \frac{3}{14}= \sqrt[14]{x^3}$

4 0

3 years ago

Kent worked in the houseware section of a department store. This year he set a record high for vacuum sales with567 vacuum sold.

Gemiola [76]

First subtract the original high from the new high:
567 - 540 = 27 more vacuums sold.

Now divide the increase amount by the original high and multiply that by 100 to get the percentage:

27 / 540 = 0.05

0.05 * 100 = 5% Increase.

5 0

3 years ago

Rewrite the rational exponent as a radical exponent

miv72 [106K]

$\bf a^{\frac{ n}{ m}} \implies \sqrt[ m]{a^ n} \\\\
-------------------------------\\\\
\sqrt[3]{2^7}\implies 2^{\frac{7}{3}}$

5 0

3 years ago

How do i do this? i'm so lost. please explain and show your work

elena-s [515]

You want to make sure to factor each equation as much as you can first.
So just focus on the numerator first. $x^3-6x^2+8x$
To factor the numerator:
$(x)(x^2-6x+8)$ factor out an x
$(x)(x-4)(x-2)$ factor out the rest completely.

Now for the denominator: $-4x^2+4x+24$
$(-4)(x^2+x+6)$ factor out a -4
$(-4)(x+3)(x-2)$ factor out the rest.

This leaves you with:
$\frac{(x)(x-4)(x-2)}{(-4)(x+3)(x-2)}$

Then you can simplify:
$\frac{(x)(x-4)}{(-4)(x+3)}$

I'm not sure what you're supposed to find exactly, so if you need more help you can ask me (:

8 0

4 years ago