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3 years ago

What is the solution to this inequality? (x | x < 7)

Mathematics

1 answer:

VARVARA [1.3K]3 years ago

8 0

Answer: The answer is at the bottom.

Step-by-step explanation:

Write

as a piecewise.

Tap for more steps...

{

≥

−

Solve

when

≥

Tap for more steps...

≤

√

Solve

−

when

Tap for more steps...

Find the union of the solutions.

√

The result can be shown in multiple forms.

Inequality Form:

√

Interval Notation:

(

−

∞

√

)

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suppose that prices of a certain model of new homes are normally distributed with a mean of $150,000. use the 68-95-99.7 rule to

Lelechka [254]

152700 is answer. Try to do these problems on paper then you can see where you went wrong . also try to do the actual question

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3 years ago

When the author visited Dublin, Ireland (home of Guinness Brewery employee William Gosset, who first developed the t distributio

disa [49]

Answer:

The Decision Rule

Fail to reject the null hypothesis

The conclusion

There is no sufficient evidence to support the claim that the mean age of the cars is greater than that of taxi

Step-by-step explanation:

From the question we are told that

The data is

Car Ages 4 0 8 11 14 3 4 4 3 5 8 3 3 7 4 6 6 1 8 2 15 11 4 1 6 1 8

Taxi Ages 8 8 0 3 8 4 3 3 6 11 7 7 6 9 5 10 8 4 3 4

The level of significance $\alpha = 0.05$

Generally the null hypothesis is $H_o : \mu_1 - \mu_2 = 0$

the alternative hypothesis is $H_a : \mu_1 - \mu_2 > 0$

Generally the sample mean for the age of cars is mathematically represented as

$\= x_1 = \frac{\sum x_i }{n}$

=> $\= x_1 = \frac{4+ 0+ 8 +11 + \cdots + 8
}{27}$

=> $\= x_1 = 5.56$

Generally the standard deviation of age of cars

$\sigma _1 = \sqrt{\frac{\sum (x_i - \= x)^2}{n_1} }$

=> $\sigma _1 = \sqrt{\frac{(4 - 5.56)^2 + (0 - 5.56)^2+ (8 - 5.56)^2 + \cdots + 8}{ 27} }$

=> $\sigma _1 = 3.88$

Generally the sample mean for the age of taxi is mathematically represented as

$\= x_2 = \frac{\sum x_i }{n}$

=> $\= x_2 = \frac{8 +8 +0 + \cdots + 4
}{20}$

=> $\= x_2 = 5.85$

Generally the standard deviation of age of taxi

$\sigma _2 = \sqrt{\frac{\sum (x_i - \= x)^2}{n_1} }$

=> $\sigma _2 = \sqrt{\frac{(8 - 5.85)^2 + (8 - 5.85)^2+ (0 - 5.85)^2 + \cdots + 8}{ 20} }$

=> $\sigma _2 = 2.83$

Generally the test statistics is mathematically represented as

$t = \frac{(\= x_ 1 - \= x_2 ) - 0}{\sqrt{\frac{\sigma^2_1}{n_1} + \frac{\sigma^2_2}{n_2} } }$

=> $t = \frac{(5.56 - 5.85 ) - 0}{\sqrt{\frac{(3.88)^2}{27} + \frac{(2.83)}{20} }}$

=> $t = -0.30$

Generally the degree of freedom is mathematically represented as

$df = n_1 + n_2 -2$

$df = 27 + 20 -2$

$df = 45$

From the t distribution table the $P(t > t )$ at the obtained degree of freedom = 45 is

$P(t > -0.30 ) = 0.61722067$

So the p-value is

$p-value = P(t > T) = 0.61722067$

From the obtained values we see that the p-value > $\alpha$ hence we fail to reject the null hypothesis

Hence the there is no sufficient evidence to support the claim that the mean age of the cars is greater than that of taxi

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3 years ago

Find the geometric mean between 9 and 11

klio [65]

Step-by-step explanation:

Geometric mean is the square root of the product.

√(9 × 11) = √99 ≈ 9.950

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3 years ago

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Licemer1 [7]

The solution to the quadratic equation 3x² + 8x - 10 by using the quadratic formula is x = 0.927 or -3.594

<h3>Solving quadratic equations.</h3>

Quadratic equations are algebraic expressions that are represented in the power of the second degree. They usually take the form ax² + bx + c

From the given information, we are to solve the quadratic equation:

3x² + 8x - 10

Using the quadratic formula:

$\mathbf{=\dfrac{-b \pm \sqrt{b^2 - 4ac}}{2a}}$

where:

a = 3
b = + 8
c = - 10

$\mathbf{= \dfrac{-(8)) \pm \sqrt{(8)^2 - 4(3 \times (-10))}}{2(3)}}$

$\mathbf{= \dfrac{-(8)) \pm \sqrt{64 -4 (-30)}}{6}}$

$\mathbf{= \dfrac{-(8)) \pm \sqrt{64+120}}{6}}$

x = 0.927 or -3.594

Learn more about solving quadratic equations here:

brainly.com/question/8649555

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2 years ago

Which expression is equivalent to<br> (2x + 1)?

Akimi4 [234]

Answer:

Step-by-step explanation:

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3 years ago

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