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Jobisdone [24]
3 years ago
9

The sides and bottom of the pool need to be tiled. The Tyler always orders 10% more than he needs to allow for breakages. How ma

ny m2 of tiles should the Tiler order

Mathematics
1 answer:
Advocard [28]3 years ago
6 0

Step-by-step explanation:

3 <em><u>poooooooooooooooooooo</u></em>

You might be interested in
7. Two measures of two angles of a triangle are 68° and 70°. Explain how to find the measure of the third angle.
Akimi4 [234]
68+70=180
=138=180
=180-138
=42 degrees (using angle sum property of triangles

Hope this helps you
3 0
3 years ago
Which equation is equivalent to -2(x+4)-(3x+8)
Studentka2010 [4]

Answer:

−  5  x  −  16

Step-by-step explanation:

-2*x and -2*4= -2x+-8

-2x+3x= -5x

-8-8= -16

-5x-16

4 0
4 years ago
I need help with number 46.
grigory [225]

Answer:

1:3

Step-by-step explanation:

1/3:1

We want the ratio with whole numbers

Multiply each side by 3

1/3*3 : 1*3

1:3

6 0
3 years ago
Plzz help Solve for x x ÷3 3/10 =2 2/5
Svet_ta [14]

Answer:

\huge\boxed{x=7\dfrac{23}{25}}

Step-by-step explanation:

x\div3\dfrac{3}{10}=2\dfrac{2}{5}\\\\\text{convert the mixed number to the impropper fraction}\\\\3\dfrac{3}{10}=\dfrac{3\cdot10+3}{10}=\dfrac{33}{10}\\\\2\dfrac{2}{5}=\dfrac{2\cdot5+2}{5}=\dfrac{12}{5}\\\\x\div\dfrac{33}{10}=\dfrac{12}{5}\\\\x\times\dfrac{10}{33}=\dfrac{12}{5}\qquad\text{multiply both sides by}\ \dfrac{33}{10}\\\\x\times\dfrac{10\!\!\!\!\!\diagup}{33\!\!\!\!\!\diagup}\times\dfrac{33\!\!\!\!\!\diagup}{10\!\!\!\!\!\diagup}=\dfrac{12}{5}\times\dfrac{33}{10}\\\\x=\dfrac{396}{50}

x=\dfrac{198}{25}\\\\x=\dfrac{175+23}{25}\\\\x=\dfrac{175}{25}+\dfrac{23}{25}\\\\x=7\dfrac{23}{25}

3 0
3 years ago
The first derivative of x^2+2y^2=16 is -x/(2y), the second is -(2y^2+x^2)/(4y^3). Find the third implicit derivative of x^2+2y^2
gtnhenbr [62]

Answer:

d³y/dx³ = (-2xy² − 3x³ − 4xy²) / (8y⁵)

Step-by-step explanation:

d²y/dx² = (-2y² − x²) / (4y³)

Take the derivative (use quotient rule and chain rule):

d³y/dx³ = [ (4y³) (-4y dy/dx − 2x) − (-2y² − x²) (12y² dy/dx) ] / (4y³)²

d³y/dx³ = [ (-16y⁴ dy/dx − 8xy³ − (-24y⁴ dy/dx − 12x²y² dy/dx) ] / (16y⁶)

d³y/dx³ = (-16y⁴ dy/dx − 8xy³ + 24y⁴ dy/dx + 12x²y² dy/dx) / (16y⁶)

d³y/dx³ = ((8y⁴ + 12x²y²) dy/dx − 8xy³) / (16y⁶)

d³y/dx³ = ((2y² + 3x²) dy/dx − 2xy) / (4y⁴)

Substitute:

d³y/dx³ = ((2y² + 3x²) (-x / (2y)) − 2xy) / (4y⁴)

d³y/dx³ = ((2y² + 3x²) (-x) − 4xy²) / (8y⁵)

d³y/dx³ = (-2xy² − 3x³ − 4xy²) / (8y⁵)

8 0
4 years ago
Read 2 more answers
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