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balandron [24]
3 years ago
9

What is the real number of the square root of -64

Mathematics
1 answer:
zhenek [66]3 years ago
4 0
Its -8 just think of 8 x 8= 64
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Tonya has 39 packages. Each package weighs 6 pounds. Choose the best estimate of the total weight of the packages.
Sidana [21]

Step-by-step explanation:

If were estimating, 39 is pretty close to 40 and 40x6 is 240 pounds. if we are getting exact about it, then 234 pounds

5 0
2 years ago
Can someone please help me with question 42?
Pavlova-9 [17]
These angles should add to 180 degrees because the angles are on a straight line so you should use the formula x=180-90-38. Therefore, x should be 52 degrees
8 0
3 years ago
This is really improtant
Oduvanchick [21]
To determine the lines that are parallel, you will need to find the missing angle length in the pairs of supplementary angles (totaling 180 degree).

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4 0
2 years ago
Resolve into partial fractions 7-5x/2x^2+x-1​
Flauer [41]

The decomposition of partial fractions is to start with the simplified reply and then take it apart, to "decompose" the final expression into its initial polynomial fractions.

Given:

\to \bold{\frac{7-5x}{2x^2+x-1}}\\\\

To find:

partial fractions=?

Solution:

\to \bold{\frac{7-5x}{2x^2+x-1}}\\\\\to \bold{\frac{7-5x}{2x^2+x(2-1)-1}}\\\\\to \bold{\frac{7-5x}{2x^2+2x-x-1}}\\\\\to \bold{\frac{7-5x}{2x(x+1)-1(x+1)}}\\\\\to \bold{\frac{7-5x}{(2x-1)(x+1)} = \frac{A}{(2x-1)} - \frac{B}{(x+1)} }\\\\\to \bold{7-5x = \frac{A ((2x-1)(x+1))}{(2x-1)} - \frac{B((2x-1)(x+1))}{(x+1)} }\\\\\to \bold{7-5x = A(x+1) -B(2x-1) }\\\\

putting x=-1

\to \bold{7-5(-1) = A(-1+1) -B(2(-1)-1) }\\\\\to \bold{7+5 = A(0) -B(-2-1) }\\\\\to \bold{12 = +3B }\\\\\to \bold{B = \frac{12}{3} }\\\\\to \bold{B = 4 }\\\\

putting x= \frac{1}{2}

\to \bold{7-5(\frac{1}{2}) = A(\frac{1}{2}+1) -B(2(\frac{1}{2})-1) }\\\\\to \bold{7-\frac{5}{2} = A(\frac{3}{2}) -B((\frac{2}{2})-1) }\\\\\to \bold{7-\frac{5}{2} = A(\frac{3}{2}) -B(1-1) }\\\\\to \bold{\frac{14-5}{2} = A(\frac{3}{2}) -B(0) }\\\\\to \bold{\frac{9}{2} = A(\frac{3}{2})}\\\\\to \bold{\frac{9}{2}  \times \frac{2}{3} = A}\\\\\to \bold{\frac{9}{3} = A}\\\\\to \bold{A=3}\\\\

So, the final answer is "\bold{\frac{7-5x}{(2x-1)(x+1)} = \frac{3}{(2x-1)} - \frac{4}{(x+1)} }\\\\".

Learn more:

brainly.com/question/22286068

3 0
3 years ago
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