Question

9th grade alg 1 number 43 and work please!

Answer 1

Answer:

Look below

Step-by-step explanation:

The equation is y=mx+b where m is the slope and b is the y-intercept.

We can find this by first calculating the slope by using any two x and y values

$Slope = \frac{rise}{run} = \frac{y_{2}-y_{1}}{x_{2}-x_{1} } = \frac{-12+2}{3-1} =\frac{-10}{2} =-5$

Now we can plug the slope back into the equation to solve for the y-intercept

y=-5x+b

-12=-5(3)+b

-12=-15+b

b=3

Therefore the equation is y=-5x+3

Now we plug in the values for x/y to complete the table

y=-5(0)+3=0+3=3

y=-5(2)+3=-10+3=-7

68=-5x+3

65=-5x

x=-13

y=-5(25)+3=-125+3=-122

So the missing values (in order from left to right) are:

3, -7, -13, and -122

Answer 2

Answer:

The rule is y = -7x + 5

→ Other values of x;

• -9

→ Other values of y;

• 5
• -2
• -9
• -12
• 28
• 68
• -170

Step-by-step explanation:

» Take points (1, -2) and (3, -12) from the table.

☑ General equation of a line is y = mx + c

• m is the slope
• c is y-intercept

✍ For slope, m :

${ \tt{slope = \frac{ - 12 - 2}{3 - 1} }} \\ \\ { \tt{slope = \frac{ - 14}{2} }} \\ \\ { \tt{m = - 7}}$

✍ For y-intercept, c :

${ \tt{y = mx + c}}$

» Taking point (1, -2):

${ \tt{ - 2 = (1 \times - 7) + c}} \\ { \tt{c = - 2 + 7}} \\ { \tt{c = 5}}$

${ \boxed{ \tt{y = - 7x + 5}}}$