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siniylev [52]
3 years ago
12

Solve each question for the variable.

Mathematics
1 answer:
luda_lava [24]3 years ago
7 0

Answer:

d=2,866

Step-by-step explanation:

7134+d=10000

Subtract 7,134 from both sides.

7134+d-7134 = 10,000 -7134

d=2866

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In a small Library there are five non-fiction books for every nine fiction book there are 130 Non-fiction books how many fiction
vova2212 [387]

Answer:

For 130 non-fiction books, the number of fiction books can be from 270 to 278.

Step-by-step explanation:

Given that, there are 5 non-fiction books for every 9 fiction books.

Observe that, if the number of fiction books is less than 9, than there will be no no-fiction books.

So, there are 5 non-fiction books for every 9 to (9+8) fiction books

So, by elementary method, there will be 5n non-fiction books for every 9n+8 fiction books, where n is a natural number.

Or, if the number of non-fiction books is 5n, then the number of fiction books will be ranging from 9n to (9n+8).

For, 150 non-fiction books, 5n=150 or n=150/5=30.

Hence, the number of fiction books can be from 9n to (9n+8).

=9x30 to (9x30+8)

=270 to 278.

Hence, for 130 non-fiction books, the number of fiction books can be from 270 to 278.

6 0
3 years ago
What is the answer to this <br> 25=-7(x+5)+5x
Aleksandr [31]

Answer:

x = -25

Step-by-step explanation:

25 = -7(x + 5) + 5x

25 = -7x - 25 + 5x

5x - 7x - 25 = 25

5x - 7x - 25 + 25 = 25 + 25

5x - 7x = 50

-2x = 50

-2x/-2 = 50/-2

x = -25

3 0
3 years ago
Read 2 more answers
If x divided 9=9 how do u know what x is
Volgvan
X is 1 because if you times it by x it equals it number
7 0
3 years ago
Read 2 more answers
Find m L<br> M<br> 8.2<br> 100°<br> P<br> 8<br> 7.<br> 29°<br> 13<br> Q<br> 3<br> N<br> m 0
Virty [35]

Answer:

bet

Step-by-step explanation:

5 0
3 years ago
Given the matrices: 1 2 A= 1 -1 2 1 1 B= 3 4 Calculate AB: C11 C12 [2.1] х 1 2 3 4 C21 C22 C11 = C12 = -2 C22 - C215 DONE​
eduard

Answer:

\:c_{11}=-2,\:\:\:c_{12}=-2

\:c_{21}=5,\:\:\:c_{22}=8

Step-by-step explanation:

Given the matrices

A=\begin{pmatrix}1&-1\\ 2&1\end{pmatrix}

B=\begin{pmatrix}1&2\\ \:3&4\end{pmatrix}

Calculating AB:

\begin{pmatrix}1&-1\\ \:\:2&1\end{pmatrix}\times \:\begin{pmatrix}1&2\\ \:\:3&4\end{pmatrix}=\begin{pmatrix}c_{11}&c_{12}\\ \:\:\:c_{21}&c_{22}\end{pmatrix}

Multiply the rows of the first matrix by the columns of the second matrix

                                   =\begin{pmatrix}1\cdot \:1+\left(-1\right)\cdot \:3&1\cdot \:2+\left(-1\right)\cdot \:4\\ 2\cdot \:1+1\cdot \:3&2\cdot \:2+1\cdot \:4\end{pmatrix}

                                   =\begin{pmatrix}-2&-2\\ 5&8\end{pmatrix}

Hence,

\begin{pmatrix}c_{11}&c_{12}\\ \:\:\:c_{21}&c_{22}\end{pmatrix}=\begin{pmatrix}-2&-2\\ \:5&8\end{pmatrix}

Therefore,

\:c_{11}=-2,\:\:\:c_{12}=-2

\:c_{21}=5,\:\:\:c_{22}=8

5 0
3 years ago
Read 2 more answers
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