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aev [14]
3 years ago
13

help please Compute the volume of a sphere with a radius of 6 inches. a. 864π in3 b.72π in3 c. 216π in3 d. 288π in3

Mathematics
1 answer:
Neporo4naja [7]3 years ago
7 0

Answer:

d. 288π in3

Step-by-step explanation:

The volume of a sphere is given by

V = 4/3 pi r^3

The radius is 6

V = 4/3 pi 6^3

V = 288 pi in^3

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A circle with the diameter of 20 mm is showing what is the exact Sir conference obvious and then question to what is the approxi
yaroslaw [1]

Answer:

The approximate circumference is 62.8 mm

Step-by-step explanation:

Circumference is basically the perimeter of the circle

Circumference is given by

2 *\pi *r

Here the diameter is 20 mm, so the radius will be half of diameter = 10 mm

Substituting the given values, in above equation, we get -

Circumference =

2 *3.14 * 10 \\62.8mm

The approximate circumference is 62.8 mm

3 0
3 years ago
It’s probably rlly simple I just dk how to do it :)
Helga [31]

Answer:

18,0

Step-by-step explanation:

By useing desmos, the line has an x intercept of 18 making that the answer.

 

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Answer:

x + 8

Step-by-step explanation:

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If three bakers can prepare 15
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45 cakes/3 hours

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3 years ago
Expand (2x -3y)^5 using the given formula.
horrorfan [7]
(2x-3y)^5

(2x-3y)(2x-3y)(2x-3y)(2x-3y)(2x-3y)

1st and 2nd power :
(2x-3y)(2x-3y) = 2x(2x-3y)-3y(2x-3y) = 4x² - 6xy - 6xy + 9y²
= 4x² - 12xy + 9y²

3rd power:
(2x-3y)(4x² - 12xy + 9y²) = 2x(4x² - 12xy + 9y²) - 3y(4x² - 12xy + 9y²)
8x³ - 24x²y + 18xy² - 12x²y +36xy² - 27y³
8x³ - 24x²y - 12x²y + 18xy² + 36xy² - 27y³
8x³ - 36x²y + 54xy² - 27y³

4th power
(2x-3y)(8x³ - 36x²y + 54xy² - 27y³) = 2x(8x³ - 36x²y + 54xy² - 27y³) -3y(8x³ - 36x²y + 54xy² - 27y³) = 16x^4 - 72x³y + 108x²y² - 54xy³ - 24x³y + 108x²y² - 162xy³ + 81y^4
16x^4 - 72x³y - 24x³y + 108x²y² + 108x²y² - 54xy³ - 162xy³ + 81y^4
16x^4 - 96x³y + 216x²y² - 216xy³ + 81y^4

5th power
(2x-3y)(<span>16x^4 - 96x³y + 216x²y² - 216xy³ + 81y^4)
2x(</span>16x^4 - 96x³y + 216x²y² - 216xy³ + 81y^4) - 3y(<span>16x^4 - 96x³y + 216x²y² - 216xy³ + 81y^4)
= 32x^5 - 192x^4y + 432x</span>³y² - 432x²y³ + 162xy^4 - 48x^4y + 288x³y² - 648x²y³ + 648xy^4 - 243y^5

32x^5 - 192x^4y -48x^4y + 432x³y² + 288x³y² - 432x²y³ - 648x²y³ + 162xy^4 + 648xy^4 - 243y^5

32x^5 - 240x^4y + 720x³y² - 1,080x²y³ + 810xy^4 - 243y^5
3 0
4 years ago
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