All categories

2 years ago

2) Which of the following represents an equation of a line parallel to one whose equation is 2y + 8x = 18?

2 answers:

3 0

Parallel has the same slope
2y + 8x = 18
Make it slope in form: y = mx + b
Divide the equation by 2
y + 4x = 9
Now subtract 4x
Y = -4x + 9
The slope is -4
Which equation also has same slope?

Solution: A

beks73 [17]2 years ago

3 0

Answer:

-by-step explanation:

i have that exact question

You might be interested in

Use the expression 28b - 4c. Part B: What is the value of the expression when b = -4 and c = 1? Show your work or explain.

Brilliant_brown [7]

Answer:

The value of the expression is -116

Step-by-step explanation:

Given

$Expression: 28b - 4c$

Required

Solve when b = -4 and c = 1

$Expression: 28b - 4c$

Substitute -4 for b and 1 for c

$Expression: 28*-4 - 4*1$

$Expression = -28*4 - 4$

$Expression = =112 - 4$

$Expression: -116$

<em>The value of the expression is -116</em>

3 0

2 years ago

Mike jogged a total distance of 5 and 1 over 3 miles during the months of october and November. if mike only jogged 1 over 6 mil

Ksivusya [100]

Mike jogged a total of A 5 and 1/3 times 1/6
your welcome.

4 0

2 years ago

Read 2 more answers

Please help!!!! It's due to tm! NO LINK

alexgriva [62]

Answer:

the answer for X is -6

Step-by-step explanation:

g(X)=5/2x -1 and g(X)= - 1

sub -16 on g(X)

-16=5/2x -1

-16+1 = 5/2x

-15 = 5/2x

divide both sides by 5/2

X= -6

4 0

3 years ago

(-w^3 + 8w^2 – 3w) + (-8w^2 + w + 3) =

kherson [118]

The expression simplified is -w^3-2w+3

I hope this helped

4 0

3 years ago

Help me please by solving and showing the steps:)

Lorico [155]

Answer:

$-\frac{3\sqrt[3]{t} }{2}$

Step-by-step explanation:

1: Write g(t) as y, resulting in $y=-\frac{8}{27}t^3$

2: Interchange the variables y and t, resulting in $t=-\frac{8}{27}y^3$

3: Multiply both sides by 27, resulting in $27t=-8y^3$

4: Divide both sides by -8, resulting in $-\frac{27t}{8}=y^3$

5: Find the cube root of both sides, resulting in $\sqrt[3]{-\frac{27t}{8} }=y$

6: Apply a radical rule, resulting in $-\sqrt[3]{\frac{27t}{8} } =y$

7: Apply another radical rule, resulting in $-\frac{\sqrt[3]{27t} }{\sqrt[3]{8} } =y$

8: Simplify the denominator, resulting in $-\frac{\sqrt[3]{27t} }{2} =y$

9: Apply yet another radical rule, resulting in $-\frac{\sqrt[3]{27}\sqrt[3]{t} }{2} =y$

10: Simplify $\sqrt[3]{27}$ , resulting in $-\frac{3\sqrt[3]{t} }{2} =y$

3 0

2 years ago