B - 13
Okay, we know that Mark brought 1 notebook and the totally is 6.91 while one pencil costs $0.42.
x= number of pencils he brought.
we know the price of 1 notebook + the cost of pencils times the numbers of pencils he brought = total cost.
So the equation will be:
1.45 + 0.42x = 6.91 subtract 1.45 on both sides.
0.42x = 5.46 Then we solve for x by dividing both sides by 0.42
x= 13
So the number of pencils he brought is 13.
Alrighty
squaer base so length=width, nice
v=lwh
but in this case, l=w, so replace l with w
V=w²h
and volume is 32000
32000=w²h
the amount of materials is the surface area
note that there is no top
so
SA=LW+2H(L+W)
L=W so
SA=W²+2H(2W)
SA=W²+4HW
alrighty
we gots
SA=W²+4HW and
32000=W²H
we want to minimize the square foottage
get rid of one of the variables
32000=W²H
solve for H
32000/W²=H
subsitute
SA=W²+4WH
SA=W²+4W(32000/W²)
SA=W²+128000/W
take derivitive to find the minimum
dSA/dW=2W-128000/W²
where does it equal 0?
0=2W-1280000/W²
128000/W²=2W
128000=2W³
64000=W³
40=W
so sub back
32000/W²=H
32000/(40)²=H
32000/(1600)=H
20=H
the box is 20cm height and the width and length are 40cm
Answer: Use the distributive property to multiply 3 by y−4.
3y−12−2(y−4)
Use the distributive property to multiply −2 by y−4.
3y−12−2y+8
Combine 3y and −2y to get y.
y−12+8
Add −12 and 8 to get −4.
Anwser:
y−4
Step-by-step explanation:
Hope this helps!
Let's start by imagining a rock being thrown to the air.
Let's say that going up is the positive direction and so, going down is the negative.
The acceleration is pointing down (because of gravity) so it's always negative. While the rock is going up, it's velocity/speed is positive, but the acceleration is negative.
While the rock is going down, both acceleration and speed are negative.
This shows that the first statemente is true, but the second is false.
You can also think that if you define going DOWN as the POSITIVE direction, you can have both positive acceleration and speed, or positive acceleration and negative speed.
You would have to find the height.
To do this, you cut the triangle from the upper vertex to the base to create two new triangles.
Then you use the Law of Cosines. You could use the google calculator for this by searching “law of cosines calculator” and inputting the values, but in case of a test, the formula is a^2 = b^2 + c^2 - 2bc cosA
If you could provide an example of a triangle, I will gladly help you with the steps! Hope this helped!
