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netineya [11]
3 years ago
10

Al oeste de Albuquerque, Nuevo México, la carretera 40 con rumbo al este es recta y tiene una fuerte pendiente hacia la ciudad.

La carretera tiene una rasante del 6%, lo cual quiere decir que su pendiente es -100 Al manejar por esta carretera usted puede ver por los señalamientos que ha bajado 1000 pies. ¿Cuál es el cambio en la distancia horizontal?
Mathematics
1 answer:
alexgriva [62]3 years ago
3 0

Usando el concepto de pendiente, se encuentra que el cambio en la distancia horizontal es de 10 pies.

La pendiente de una reta es la <u>razón entre el cambio vertical y el cambio horizontal,</u> o sea, cual el cambio vertical cuando el cambio horizontal es de 1.

En este problema, hay que:

  • La pendiente es -100, o sea, cuando hay un desplazamiento de un pie por adelante, hay una queda de 100 pies.
  • Bajado 1000 pies, entonces, aplicando la proporción:

1 pie H -> -100 pies V

x pie H -> -1000 pies V

Aplicando la multiplicación cruzada:

-100x = -1000

100x = 1000

x = \frac{1000}{100}

x = 10

El cambio en la distancia horizontal es de 10 pies.

Un problema similar es dado en brainly.com/question/24766917

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Step-by-step explanation:

Since radar reports 30 tracks in one minute in which 60 seconds makes 1 minute

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Answer:

<em>M(13)=14.3 gram</em>

Step-by-step explanation:

<u>Exponential Decay Function</u>

The exponential function is used to model natural decaying processes, where the change is proportional to the actual quantity.

An exponential decaying function is expressed as:

C(t)=C_o\cdot(1-r)^t

Where:

C(t) is the actual value of the function at time t

Co is the initial value of C at t=0

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The element has an initial mass of Mo=970 grams, the decaying rate is r=27.7% = 0.277 per minute.

The equation of the model is:

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