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netineya [11]
3 years ago
10

Al oeste de Albuquerque, Nuevo México, la carretera 40 con rumbo al este es recta y tiene una fuerte pendiente hacia la ciudad.

La carretera tiene una rasante del 6%, lo cual quiere decir que su pendiente es -100 Al manejar por esta carretera usted puede ver por los señalamientos que ha bajado 1000 pies. ¿Cuál es el cambio en la distancia horizontal?
Mathematics
1 answer:
alexgriva [62]3 years ago
3 0

Usando el concepto de pendiente, se encuentra que el cambio en la distancia horizontal es de 10 pies.

La pendiente de una reta es la <u>razón entre el cambio vertical y el cambio horizontal,</u> o sea, cual el cambio vertical cuando el cambio horizontal es de 1.

En este problema, hay que:

  • La pendiente es -100, o sea, cuando hay un desplazamiento de un pie por adelante, hay una queda de 100 pies.
  • Bajado 1000 pies, entonces, aplicando la proporción:

1 pie H -> -100 pies V

x pie H -> -1000 pies V

Aplicando la multiplicación cruzada:

-100x = -1000

100x = 1000

x = \frac{1000}{100}

x = 10

El cambio en la distancia horizontal es de 10 pies.

Un problema similar es dado en brainly.com/question/24766917

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y − 7 = − 6 /11 ⋅ ( x + 7 )

Step-by-step explanation:

Find the point-slope form.

Point-slope formula: y-y₁=m(x-x₁)

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Step-by-step explanation:

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3 years ago
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Let f(x) = 3x - 10. Find the value of f(-3).
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Easy, sub -3 for x
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6 0
3 years ago
Find all the missing elements:
pentagon [3]

Answer:

B = 34.2°

C = 58.2° or 121.8°

c= 10.6

Step-by-step explanation:

Step 1

Finding c

We calculate c using Pythagoras Theorem

c²= a² + b²

c = √a² + b²

a= 8, b = 7

c = √8² + 7²

c = √64 + 49

c = √(113)

c = 10.630145813

Approximately c = 10.6

Step 2

Find B

We solve this using Sine rule

a/sin A = b/sin B

A = 40°

a = 8

b = 7

Hence,

8/sin 40° = 7/sin B

8 × sin B = sin 40° × 7

sin B = sin 40° × 7/8

B = arc sin (sin 40° × 7/8)

B ≈34.22465°

Approximately = 34.2°

Step 3

We find C

Find B

We solve this using Sine rule

b/sin B = c/sin C

B = 34.2°

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c = 10.6

C = ?

Hence,

7/sin 34.2° = 10.6/sin C

7 × sin C = sin 34.2 × 10.6

sin C = sin 34.2° × 10.6/7

C = arc sin (sin 34.2° × 10.6/7)

C = arcsin(0.85)

C= 58.211669383

Approximately C = 58.2°

Or = 180 - 58.2

C = 121.8°

5 0
3 years ago
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Parallelogram R S T U is shown. Angle S is 70 degrees.
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Answer:

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The opposite angles of the parallelogram are the same.

From the diagram;

<S = <U and <R = <T

Given

<S = 70°

Since <S = <U, hence <U = 70°

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3 years ago
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