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allochka39001 [22]
3 years ago
11

I need help please make sure this is correct

Mathematics
2 answers:
In-s [12.5K]3 years ago
5 0

Answer:

the answer is a

Step-by-step explanation:

congruent means that the shapes are the same size and shape which means that a is the answer

german3 years ago
3 0

Answer:a

Step-by-step explanation:

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Which point on the graph could represent the ratio of 2 white flowers for every 3 pink flowers that will be in one row of Molly’
vekshin1

Answer: It’s B

Step-by-step explanation:

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4 years ago
A business trip reimbursed $0.55 per mile. Mr. Jackson has a budget of $70 for the round trip. If he is traveling to a town 61 m
erastova [34]

Answer:

3355

Step-by-step explanation:

55 x 61 = 3355

8 0
3 years ago
You spent $10 on office supplies out of a $25 budget.What percent of your budget did you spend?
lana66690 [7]
You spent 40% of your budget. 

10/25=2/5=40/100
6 0
3 years ago
Rewrite the rational exponent as a radical by extending the properties of integer exponents. 2 7/8 divided by 2 1/4
VladimirAG [237]
We know the rule of change: a b/c= (ac+b):c
So we have 2 7/8= (2x8+7):8= 23/8
and the second: 2 1/4 = (2x4+1):4= 9/4
We do the division: 23/8: 9/4= 23/8 x 4/9= (23x4):(8x9)= 23/18= 1  5/18
7 0
4 years ago
Evaluate Dx / ^ 9-8x - x2^
Solnce55 [7]
It depends on what you mean by the delimiting carats "^"...

Since you use parentheses appropriately in the answer choices, I'm going to go out on a limb here and assume something like "^x^" stands for \sqrt x.

In that case, you want to find the antiderivative,

\displaystyle\int\frac{\mathrm dx}{\sqrt{9-8x-x^2}}

Complete the square in the denominator:

9-8x-x^2=25-(16+8x+x^2)=5^2-(x+4)^2

Now substitute x+4=5\sin y, so that \mathrm dx=5\cos y\,\mathrm dy. Then

\displaystyle\int\frac{\mathrm dx}{\sqrt{9-8x-x^2}}=\int\frac{5\cos y}{\sqrt{5^2-(5\sin y)^2}}\,\mathrm dy

which simplifies to

\displaystyle\int\frac{5\cos 
y}{5\sqrt{1-\sin^2y}}\,\mathrm dy=\int\frac{\cos y}{\sqrt{\cos^2y}}\,\mathrm dy

Now, recall that \sqrt{x^2}=|x|. But we want the substitution we made to be reversible, so that

x+4=5\sin y\iff y=\sin^{-1}\left(\dfrac{x+4}5\right)

which implies that -\dfrac\pi2\le y\le\dfrac\pi2. (This is the range of the inverse sine function.)

Under these conditions, we have \cos y\ge0, which lets us reduce \sqrt{\cos^2y}=|\cos y|=\cos y. Finally,

\displaystyle\int\frac{\cos y}{\cos y}\,\mathrm dy=\int\mathrm dy=y+C

and back-substituting to get this in terms of x yields

\displaystyle\int\frac{\mathrm dx}{\sqrt{9-8x-x^2}}=\sin^{-1}\left(\frac{x+4}5\right)+C
4 0
3 years ago
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