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vredina [299]
3 years ago
9

Which expression is equivalent to

Mathematics
2 answers:
Aleks04 [339]3 years ago
6 0

Answer:

I think the answer is C

Step-by-step explanation:

solmaris [256]3 years ago
5 0

Answer:

C

Step-by-step explanation:

-4(8-3) =

-4(5) = -20

C) -32 + 12 = -20

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Galina-37 [17]

Answer:

Did you find the answer???

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3 years ago
Identify the multiplication property used in the equation 7x2=2x7
stiks02 [169]
The associative property
3 0
3 years ago
Which function below has the lowest y intercept?
neonofarm [45]

Our first function is g(x). <em>Al had two dozen donuts </em>means that <em>two dozen</em> is the y-intercept of this function. A dozen equals 12, therefore two dozens is 24. <em>Every cubicle he passed, he lost 2 donuts </em>is the slope of the function and it is negative, that is -2, thus:


g(x)=-2x+24 \\ \\ \boxed{y-intercept = 24}


The second equation is h(x):


h(x)=6x+1

So:

\boxed{y-intercept=1}


From the graph, we can see that the f(x) intersects the y-axis at:


\boxed{y-intercept=2}


Accordingly, h(x) has the lowest y intercept.


<em>In conclusion, the right answer is c.h(x)</em>

6 0
4 years ago
Read 2 more answers
Check all that apply
Pavlova-9 [17]
Get her done ...........................
5 0
3 years ago
The friendly sausage factory (fsf) can produce hot dogs at a rate of 5,000 per day. fsf supplies hot dogs to local restaurants a
juin [17]

Answer:

a. 21 327 hot dogs/run

b. 70 runs/yr

c. 4 da/run

Step-by-step explanation:

Data:

Production rate (p)           = 5000/da

Usage rate (u)                  =    260/da

Setup cost (S)                   = $66

Annual carrying cost (H) = $0.45/hot dog

Production days (d)         = 294 da

Calculations:

a. Optimal run size

(i) Annual demand (D) = pd = (5000 hot dogs/1 day) × (294 days/1 yr)

= 1 470 000 hot dogs/yr

(ii) Economic run size

Q_{0}= \sqrt{\frac{2DS }{ h}\times\frac{ p}{p-u }}

= \sqrt{\frac{2\times1470000\times66 }{ 0.45}\times\frac{ 5000}{5000-260 }}

= \sqrt{431200000\times\frac{ 5000}{4740 }}

= \sqrt{454852321}

= 21 327 hot dogs/run

b. Number of runs per year

Runs = D/Q₀ = (1 470 000 hot dogs/1yr) × (1 run/21 327 hotdogs)

= 70 runs/yr

c. Length of a run

Length = Q₀/p = (21 327 hot dogs/1 run) × (1 da/5000 hot dogs)

= 4 da/run

8 0
3 years ago
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