All categories

3 years ago

THERE IS NO QUESTION TAKE POINTS FOR ANSWER

Mathematics

2 answers:

jenyasd209 [6]3 years ago

8 0

Answer:

Thanks!

Step-by-step explanation:

tekilochka [14]3 years ago

4 0

Answer:

What I didn't understand

You might be interested in

Convert 7 yards 2 feet to inches. 7 yd 2 ft = __ in.

zavuch27 [327]

First, you can convert yards to feet, to make it easier to simplify feet to inches. There are 3ft in a yard, so you can say that there are 3ft*7+2ft. 3*7 is 21, and adding 2 to that you will have 23ft. from here you can convert that directly to inches. If there are 12 inches in a foot, you will multiply 12 by 23. Your final answer will be 276in.

3 0

3 years ago

Let f(x) = 4x-7 Find (f o f)(2)

bonufazy [111]

(f∘g)(2) = f(f(2)) = f(4(2)-7) = f(1) = 4(1)-7 = -3

5 0

3 years ago

An insurance company selected a random sample of 500 clients under 18 years of age and found that 180 of them had had an acciden

Butoxors [25]

Answer:

a) The pooled proportion is p=0.3.

b) P-value = 0.000078

c) Lower bound = 0.0556

d) Upper bound = 0.1644

Step-by-step explanation:

This is a hypothesis test for the difference between proportions.

The claim is that the accident proportions differ between the two age groups .

Then, the null and alternative hypothesis are:

$H_0: \pi_1-\pi_2=0\\\\H_a:\pi_1-\pi_2\neq 0$

The significance level is 0.05.

The sample 1, of size n1=500 has a proportion of p1=0.36.

$p_1=X_1/n_1=180/500=0.36$

The sample 2, of size n2=600 has a proportion of p2=0.25.

$p_1=X_1/n_1=150/600=0.25$ .

The difference between proportions is (p1-p2)=0.11.

$p_d=p_1-p_2=0.36-0.25=0.11$

The pooled proportion, needed to calculate the standard error, is:

$p=\dfrac{X_1+X_2}{n_1+n_2}=\dfrac{180+150}{500+600}=\dfrac{330}{1100}=0.3$

The standard error for the difference between proportions can now be calculated as:

The estimated standard error of the difference between means is computed using the formula:

$s_{p1-p2}=\sqrt{\dfrac{p(1-p)}{n_1}+\dfrac{p(1-p)}{n_2}}=\sqrt{\dfrac{0.3*0.7}{500}+\dfrac{0.3*0.7}{600}}\\\\\\s_{p1-p2}=\sqrt{0.00042+0.00035}=\sqrt{0.00077}=0.0277$

Then, we can calculate the z-statistic as:

$z=\dfrac{p_d-(\pi_1-\pi_2)}{s_{p1-p2}}=\dfrac{0.11-0}{0.0277}=\dfrac{0.11}{0.0277}=3.964$

This test is a two-tailed test, so the P-value for this test is calculated as (using a z-table):

$P-value=2\cdot P(t>3.964)=0.000078$

As the P-value (0.000078) is smaller than the significance level (0.05), the effect is significant.

The null hypothesis is rejected.

There is enough evidence to support the claim that the accident proportions differ between the two age groups.

If we want to calculate the bounds of a 95% confidence interval, we start by calculating the margin of error.

For a 95% CI, the critical value for z is z=1.96.

Then, the margin of error is:

$MOE=z \cdot s_{p1-p2}=1.96\cdot 0.0277=0.0544$

Then, the lower and upper bounds of the confidence interval are:

$LL=(p_1-p_2)-z\cdot s_{p1-p2} = 0.11-0.0544=0.05561\\\\UL=(p_1-p_2)+z\cdot s_{p1-p2}= 0.11+0.0544=0.16439$

The 95% confidence interval for the population mean is (0.0556, 0.1644).

5 0

3 years ago

Sharon is jumping from an 18-foot diving board with an initial upward velocity of 4 ft/sWhen Sharon jumps, Megan throws a beach

likoan [24]

Answer:

1.08 seconds

Step-by-step explanation:

given data

first equation:

According to the data, sharon position will be

h(t)= -16 $t^{2}$ + 4t +18---->eq(1)

Second equation;

When Sharon jumps, Megan throws a beach ball up to Sharon with an initial upward velocity of 16 ft/s from a height 5 feet off the ground to the nearest hundredth of a second

therefore, ball position would be

h(t)= -16 $t^{2}$ +16t +5 --->eq(2)

In order to find how long after she jumps does the ball reach Sharon i.e time, we will equate eq(1) and eq(2)

Therefore,

eq(1)= eq(2)

-16 $t^{2}$ +4t +18 = -16 $t^{2}$ + 16t +5 --->(further simplifying it)

-16 $t^{2}$ + 16 $t^{2}$ + 18 -5 = 16t - 4t

13 = 12t

t= 13/12

t= 1.08 s

Thus it took 1.08 seconds.

7 0

3 years ago

Complete the table by converting each decimal to a fraction.

AlekseyPX

if you've read those links already, you'd know what we're doing here.

we'll move the repeating part to the left-side of the dot, by multiplying by "1" and as many zeros as needed, or 10 at some power pretty much.

on 0.13 we need 100 to get 13.13.... and on 0.1234, we need 10000 to get 1234.1234....

$\bf 0.\overline{13}~\hspace{10em}x=0.\overline{13}
\\\\[-0.35em]
~\dotfill\\\\
\begin{array}{|lll|ll}
\cline{1-3}
&&\\
100\cdot 0.\overline{13}& = & 13.\overline{13}\\
100\cdot x&& 13 + 0.\overline{13}\\
100x&&13+x
\\&&\\
\cline{1-3}
\end{array}\implies \begin{array}{llll}
100x=13+x\implies 99x=13
\\\\
x=\cfrac{13}{99}
\end{array}
\\\\[-0.35em]
\rule{34em}{0.25pt}\\\\
0.\overline{1234}~\hspace{10em}x=0.\overline{1234}
\\\\[-0.35em]
~\dotfill$

$\bf \begin{array}{|ccc|ll}
\cline{1-3}
&&\\
10000\cdot 0.\overline{1234}&=&1234.\overline{1234}\\
10000\cdot x&=&1234+0.\overline{1234}\\
10000x&=&1234+x
\\&&\\
\cline{1-3}
\end{array}\implies \begin{array}{llll}
10000x=1234+x
\\\\
9999x=1234\implies x=\cfrac{1234}{9999}
\end{array}$

7 0

3 years ago

Read 2 more answers